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Margarita [4]
3 years ago
6

A candy jar contains flavored jelly beans. There are 7 orange, 9 cherry, 3 lemon, 15 licorice, and 6 blueberry. Find the probabi

lity of choosing two cherry jelly beans in a row (the first jelly bean is not replaced). PLEASE HELP!!!
Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

Answer: 0.046

Step-by-step explanation:

From the question,

orange jelly beans= 7

Cherry jelly beans =9

Lemon jelly beans = 3

Licorice jelly beans = 15

Blueberry jelly beans = 6

Total jelly beans = 40

The probability of choosing the first cherry jelly beans will be = 9/40

After the first one is chosen, there'll be 8 cherry jelly beans and total of 39 left. The probability of choosing the second one will be = 8/39

The probability of choosing two cherry jelly beans in a row will be:

= 9/40 × 8/39

= 72/1560

= 0.046

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Answer:

I think that it is  26, 51, 103,

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Step-by-step explanation:

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2 years ago
Determine which fraction is larger 3/7 or 1/3 find the common denominator
Wewaii [24]

Answer:

  • LCM is 21

{:}\leadsto\sf {\dfrac {3}{7}}

{:}\leadsto\sf {\dfrac {3×3}{7×3}}

{:}\leadsto\sf {\dfrac {9}{2}}

  • .

{:}\leadsto\sf {\dfrac {1}{3}}

{:}\leadsto\sf {\dfrac {1×7}{3×7}}

{:}\leadsto\sf {\dfrac {7}{21}}

<h2>____________________</h2>

{:}\leadsto\sf {\dfrac {9}{21}}\iff {\dfrac {7}{21}}

{:}\leadsto\sf {\dfrac{9}{21}} \gt {\dfrac {7}{21}}

\therefore\sf {\dfrac {3}{7}} \gt {\dfrac {7}{21}}

8 0
3 years ago
Find (co d)(x).<br> c(x) = 3x - 6<br> d(x) = -5x + 4<br> Please continue to help me, thank you
Andreas93 [3]

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Step-by-step explanation:

c(x) = 3x - 6

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3(-5x+4)-6=

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The third choice - 65.3%.

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The experimental probability that you make a free throw is 65.3%.
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