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Margarita [4]
3 years ago
6

A candy jar contains flavored jelly beans. There are 7 orange, 9 cherry, 3 lemon, 15 licorice, and 6 blueberry. Find the probabi

lity of choosing two cherry jelly beans in a row (the first jelly bean is not replaced). PLEASE HELP!!!
Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

Answer: 0.046

Step-by-step explanation:

From the question,

orange jelly beans= 7

Cherry jelly beans =9

Lemon jelly beans = 3

Licorice jelly beans = 15

Blueberry jelly beans = 6

Total jelly beans = 40

The probability of choosing the first cherry jelly beans will be = 9/40

After the first one is chosen, there'll be 8 cherry jelly beans and total of 39 left. The probability of choosing the second one will be = 8/39

The probability of choosing two cherry jelly beans in a row will be:

= 9/40 × 8/39

= 72/1560

= 0.046

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Wich is a better buy?4 cans for $6 or 8 cans for $10​
Oliga [24]

Answer:

Step-by-step explanation:

6/4=1.5 (price per can)

10/8=1.25 (price per can)

1.25 is cheaper than 1.5

the second one is the better buy

8 0
3 years ago
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Are the triangles similar help.
xxTIMURxx [149]

Answer:

yes the two triangles are similar

7 0
3 years ago
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2. Find the general relation of the equation cos3A+cos5A=0
mars1129 [50]
<h2>Answer:</h2>

A=\frac{\pi}{8}+\frac{n\pi}{4}or\ A=\frac{\pi}{2}+n\pi

<h2>Step-by-step explanation:</h2>

<h3>Find angles</h3>

cos3A+cos5A=0

________________________________________________________

<h3>Transform the expression using the sum-to-product formula</h3>

2cos(\frac{3A+5A}{2})cos(\frac{3A-5A}{2})=0

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<h3>Combine like terms</h3>

2cos(\frac{8A}{2})cos(\frac{3A-5A}{2})=0\\\\  2cos(\frac{8A}{2})cos(\frac{-2A}{2})=0

________________________________________________________

<h3>Divide both sides of the equation by the coefficient of variable</h3>

cos(\frac{8A}{2})cos(\frac{-2A}{2})=0

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<h3>Apply zero product property that at least one factor is zero</h3>

cos(\frac{8A}{2})=0\ or\ cos(\frac{-2A}{2})=0

________________________________________________________

<h2>Cos (8A/2) = 0:</h2>

<h3>Cross out the common factor</h3>

cos\ 4A=0

________________________________________________________

<h3>Solve the trigonometric equation to find a particular solution</h3>

4A=\frac{\pi}{2}or\ 4A=\frac{3\pi}{2}

________________________________________________________

<h3>Solve the trigonometric equation to find a general solution</h3>

4A=\frac{\pi}{2}+2n\pi \ or\\ \\ 4A=\frac{3 \pi}{2}+2n \pi\\ \\A=\frac{\pi}{8}+\frac{n \pi}{4\\}

________________________________________________________

<h2>cos(-2A/2) = 0</h2>

<h3>Reduce the fraction</h3>

cos(-A)=0

________________________________________________________

<h3>Simplify the expression using the symmetry of trigonometric function</h3>

cosA=0

________________________________________________________

<h3>Solve the trigonometric equation to find a particular solution</h3>

A=\frac{\pi }{2}\ or\ A=\frac{3 \pi}{2}

________________________________________________________

<h3>Solve the trigonometric equation to find a general solution</h3>

A=\frac{\pi}{2}+2n\pi\ or\ A=\frac{3\pi}{2}+2n\pi,n\in\ Z

________________________________________________________

<h3>Find the union of solution sets</h3>

A=\frac{\pi}{2}+n\pi

________________________________________________________

<h2>A = π/8 + nπ/4 or A = π/2 + nπ, n ∈ Z</h2>

<h3>Find the union of solution sets</h3>

A=\frac{\pi}{8}+\frac{n\pi}{4}\ or\ A=\frac{\pi}{2}+n\pi ,n\in Z

<em>I hope this helps you</em>

<em>:)</em>

5 0
2 years ago
How can I write it in a factored form?
mr_godi [17]
F(x) = (x + 1) (x - 3)
8 0
3 years ago
Suppose that a die-hardly-ever battery has an exponential time-to-failure distribution with a mean of 48 months. at 60 months, t
mel-nik [20]

Since the time to failure distribution is exponential, the distribution is F (n) = 1 – e ^ (-x/48)

The probability of failure between months 60 and 72 is the same as the probability that the battery will fail in 12 months, since the exponential distribution is memoryless F (12) = 0.221

<span> </span>

7 0
3 years ago
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