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Zinaida [17]
2 years ago
14

NO ONE WILL HELP IN ENGLISH CAN SOMEONE HELP HERE!! GIVING AWAY 20 PNTS AND GIVING BRAINLIEST TO THE BEST ANSWER!!!!!!!!!!!

Mathematics
1 answer:
olchik [2.2K]2 years ago
6 0
Are these true and false? I think it's true for both
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Sheila I said going to divide a 36-inch piece of ribbon into 5 equal pieces she says each piece will be 7 inches long
blsea [12.9K]
Well it would actually be 7.2 inches per each piece
7 0
3 years ago
The cost of 6one by two metere
Alik [6]

Answer:

Rs 17 3/4

Step-by-step explanation:

Cost of 6 1/2 m = 115 3/8

Cost of 1 m = x

  • x = 115 3/8 ÷ 6 1/2
  • x = (115*8 +3)/8 ÷ 13/2
  • x = 923/8 × 2/13
  • x = 923/(4*13)
  • x = 923/52
  • x = 17 39/52
  • x = 17 3/4

Cost of 1 meter is Rs 17 3/4

5 0
2 years ago
A survey asks, "If the husband in a family wants children, but the wife decides that she does not want any children, is it all r
vodka [1.7K]

Answer:

a. The 99% confidence interval for the population proportion is (0.7872, 0.8610).

D. Yes, we can conclude that the population proportion exceeds 75% because 75% is below the lowest believable value of the confidence interval.

b. The 99% confidence interval would be wider than a 95% confidence interval.

As the confidence level increases, the width interval increases, as we are requiring more confidence with the same information (there is no new sample). This means that, to be more confident, the only way is to include more values in the interval.

Step-by-step explanation:

We have to calculate a 99% confidence interval for the proportion.

The sample proportion is p=0.8241.

p=X/n=581/705=0.8241

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.8241*0.1759}{705}}\\\\\\ \sigma_p=\sqrt{0.000206}=0.0143

The critical z-value for a 99% confidence interval is z=2.5758.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=2.5758 \cdot 0.0143=0.0369

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.8241-0.0369=0.7872\\\\UL=p+z \cdot \sigma_p = 0.8241+0.0369=0.8610

The 99% confidence interval for the population proportion is (0.7872, 0.8610).

We can conclude that there is, at least, 99% chances that the true proportion is higher than 0.7872. So there is at least 99% chances that the population proportion is higher than 0.75.

4 0
2 years ago
Compare the values of each digits in the decimal 962.69 , compare the 6 in the tens place than the 6 in the tenths place.
givi [52]
I think the answer would be like... The 6 in each place is worth a different amount. Like just the 6 in the tenths place is worth less than the 6 in the tens place.
7 0
3 years ago
PLEASE PLEASE HELP WILL GIVE BRAINLIEST!!!!!
Kobotan [32]

Answer:

a.  2x^2 - 16x + 24.

Step-by-step explanation:

k(x) = 2x^2 − 8

p(x) = x − 4

To find ( k o p)(x) we replace the x in k(x) by x - 4:

= 2(x - 4)^2 - 8

= 2x^2 - 16x + 32 - 8

= 2x^2 - 16x + 24.

8 0
2 years ago
Read 2 more answers
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