NO ONE WILL HELP IN ENGLISH CAN SOMEONE HELP HERE!! GIVING AWAY 20 PNTS AND GIVING BRAINLIEST TO THE BEST ANSWER!!!!!!!!!!!
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Answer:
120 pounds
Step-by-step explanation:
We can use systems of equations to solve this problem. Assuming j is Jim's weight and b is Bob's weight, the equations are:
j + b = 180
b - j = 1/2b
Let's get b - j = 1/2b into standard form (b, then j, then the equal sign, then the constant.)
Now we can solve using the process of elimination.
Now we know how much Bob weighs, for fun, let's find Jim's weight by substituting into the equation.
So Bob weighs 120 pounds and Jim weight 60 pounds.
Hope this helped!
There is sufficient evidence to conclude that, the percentage of the families who own a pet is different than 60%.
<h3>What are null hypotheses and alternative hypotheses?</h3>In null hypotheses, there is no relationship between the two phenomena under the assumption that it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.
It Is said That 60% of families own a pet.
Of a sample of 95 families, 70 owned pets.
Whether the percent of families who own pets is different than 60%.
Let P be a proportion of the family who owns pets
Then by the test, we have
H₀: P = 0.60
Hₐ: P ≠ 60
Then by the test statistic, we have
Where
= sample proportion
P₀ = hypothesis proporion
n = sample size
Then we have
= x/n
= 70/95
= 0.74
Then the test statistic will be
z₀ = 2.785
Then the critical region will be
Critical value = ±
α = 0.05
α/2 = 0.025
Then we have
z₀.₀₂₅ = 1.96
Then the critical value will be
Critical value = ± 1.96
We reject if
We have
2.79 > 1.96
We reject the null hypothesis at a 5% significance level.
There is sufficient evidence to conclude that, the percentage of the families who own a pet is different than 60%.
More about the null hypotheses and alternative hypotheses link is given below.
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