Answer:
wheres the rest of the problem?
Answer:
see attached
Step-by-step explanation:
The x-coordinate of the vertex is given by ...
x = -b/(2a)
for f(x) = ax^2 +bx +c.
We see that the vertex is at x = 1, and we are given a = -16. Then we can find "b" from ...
1 = -b/(2(-16))
32 = b
We know the y-intercept of the equation is 5 (the starting height), so the equation must be ...
h(t) = -16t^2 +32t +5 . . . . . matches the last choice
Line up the decimal points and multiply the rest like you would normally do it but drop down the decimal at the end
Answer:
Step-by-step explanation:
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(6-8)^2+(4+5)^2
d^2=4+81
d^2=85
d=(85)^(1/2)
d=9.22 (rounded to nearest hundredth)
In y = mx + b form, the slope will be in the m position and the y int will be in the b position
y = -2x + 2....slope = -2 and y int = 2
y = -2x - 3.....slope = -2 and y int = -3
when u have 2 lines that both have the same slope but different y intercepts, u have parallel lines with no solution because ur lines never intersect.
so ur answer is : no solutions or 0 solutions