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vekshin1
4 years ago
5

13. Three weeks ago John bought stock at 49'/s; today the stock is valued at 49'/s. We could say the stock is performing at whic

h of the following?
A. Above par
B. Below par
C. On par
D. Par equality
Mathematics
2 answers:
Paul [167]4 years ago
4 0

Answer:

awnser b

Step-by-step explanation:

Aliun [14]4 years ago
4 0
Hello! I believe that the answer is C, on par. Have a nice day :D
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Whitepunk [10]

Answer: x=1\frac{4}{5}

<u>Simplify both sides of the equation</u>

<u></u>\frac{6}{5} =\frac{-8}{3} x+6<u></u>

<u></u>

<u>Flip the equation</u>

<u></u>\frac{-8}{3} x+6=\frac{6}{5}<u></u>

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<u>Subtract 6 from both sides</u>

<u></u>\frac{-8}{3} x+6-6=\frac{6}{5} -6<u></u>

<u></u>\frac{-8}{3} x=\frac{-24}{5}<u></u>

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<u>Multiply both sides by 3/(-8)</u>

<u></u>(\frac{3}{-8} )*\frac{-8}{3} x)=(\frac{3}{-8} )*(\frac{-24}{5} )<u></u>

<u></u>x=\frac{9}{5}<u></u>

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<u>Turn 9/5 into a Mixed Number</u>

<u></u>x=\frac{9}{5} =1\frac{4}{5} \\x=1\frac{4}{5}<u></u>

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4 years ago
Which of the following statements is false?
gulaghasi [49]
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4 years ago
A man starts walking north at 5 ft/s from a point P. Five minutes later a woman starts walking south at 6 ft/s from a point 500
aev [14]
Check the picture below.

the man is going North, and he has a rate of 5 f/s, she's going south, 500 miles from P, the green distance, and she's going 6 f/s.

by the time she started walking, he already had been walking for 5 minutes, or 300 seconds, since he's going 5 f/s, then he had already covered 1500 feet by then.

after that, they both walked for 15 minutes more or 900 seconds, and for her that means 5400 feet, whilst for him going slower means 4500 feet, as you see in the  picture.

since he's going North and she's going South, dy/dt is the combined rates, as you see there.

now, let's use the pythagorean theorem, bearing in mind that the green 500 feet are constant all the while, that matters because the derivative of a constant is 0.

\bf r^2=x^2+y^2\stackrel{chain~rule}{2r\cfrac{dr}{dt}}=0+\stackrel{chain~rule}{2y\cfrac{dy}{dt}}\implies \cfrac{dr}{dt}=\cfrac{2y}{2r}\cdot \cfrac{dy}{dt}&#10;\\\\\\&#10;\cfrac{dr}{dt}=\cfrac{y}{r}\cdot \cfrac{dy}{dt}

so, what is "r" value 15 minutes later anyway?

\bf r=\sqrt{(1500+4500+5400)^2+500^2}\implies r=\sqrt{11400^2+500^2}&#10;\\\\\\&#10;r=\sqrt{130210000}\implies r=100\sqrt{13021}

then we just plug those folks in the derivative,

\bf \cfrac{dr}{dt}=\cfrac{y}{r}\cdot \cfrac{dy}{dt}\qquad &#10;\begin{cases}&#10;r=100\sqrt{13021}\\&#10;\frac{dy}{dt}=11\\&#10;y=11400&#10;\end{cases}\implies \cfrac{dr}{dt}=\cfrac{11400}{100\sqrt{13021}}\cdot 11&#10;\\\\\\&#10; \cfrac{dr}{dt}=\cfrac{114\cdot 11}{\sqrt{13021}}\implies  \cfrac{dr}{dt}=\cfrac{1254}{\sqrt{13021}}\implies  \cfrac{dr}{dt}\approx 10.99~\frac{f}{s}

7 0
4 years ago
If the product is positive then m and n have
Crank

Answer:

Both be positive or both be negative

Step-by-step explanation:

Both be positive or both be negative

+ *+ = +

- * - = +

6 0
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Read 2 more answers
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astra-53 [7]

Answer:

y = 7/8x + 1

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According to y = mx + b, whereas b is the y-intercept

so if b is positive, b has to be larger than 0

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The #1 and #4 are wrong because they are proportional

The #2 and #4 are wrong because they have negative y-intercept

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2 years ago
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