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shtirl [24]
3 years ago
9

PLEASE HELP IM TIMED!!!!!!!!

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0

Answer:

15

Step-by-step explanation:

DanielleElmas [232]3 years ago
4 0

Answer:

stole

Step-by-step explanation:

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Write the equation of a line with slope 3 and y-intercept −3.
natta225 [31]
The equation would be y = 3x-3




4 0
3 years ago
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ILL GIVE BRAINLEST, classify the triangle below with work please :)
Minchanka [31]

Answer:

A right triangle

Step-by-step explanation:

All interior angles in a triangle are equal to 180°.

x+x+2x = 180°

4x = 180°

x = 45°

So two of the angles are 45°, and the remaining angle is 45°×2 = 90° (a right angle).

7 0
2 years ago
Mr. Lopez wrote the equation 32g+8g-10g=150 on the board. Four students explained how to solve for g. Alyssa: “I added 32 and 8
Vaselesa [24]

Answer:

Wilhem

Step-by-step explanation:

The given equation is

32g+8g-10g=150

Step 1 : Add 32g and 8g.

(32g+8g)-10g=150

(32+8)g-10g=150

40g-10g=150

Step 2: Subtract 10 from 40.

(40-10)g=150

30g=150

Step 3: Divide both sides by 30, find the value of g.

\frac{30g}{30}=\frac{150}{30}

g=5

The value of g is 5.

Therefore, Wilhem is correct.

7 0
2 years ago
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Find the second derivative of f(x)=sec(x).
marysya [2.9K]

The derivative of sec x is equal to sec x tan x. The derivative of the first derivative can be determined using the rule of products. The derivative is equal to sec x sec^2 x + tan x * sec x tan x. The simplified answer is sec^3 x + sec^2 x tan x equal to sec^2 x ( sec x + tanx ) 
8 0
3 years ago
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Spends at most 30, buys boxes of crayons that cost 2 per box, also buys a poster for 5. Wants to know how many boxes of crayons
My name is Ann [436]

Answer:

for 15 crayons box she can spend

Step-by-step explanation:

The computation of the number of crayons for which she can spend is shown below:

Given that

She can spend $30

And, the cost is 2 per box

So, for the number of crayons for which she can spend is

= $30 ÷ 2

= 15 crayons box

Hence, for 15 crayons box she can spend

The same would be relevant

4 0
3 years ago
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