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3 years ago

Solve: 20x-18<50<36x-16

1 answer:

lina2011 [118]3 years ago

7 0

So this is actually composed o 2 sentances
20x-18<50 AND 50<36x-16
so solve each and find solutions where x is the same in both sentances
20x-18<50
add 18 to both sides
20x<68
divide both sides by 20
x<3 and 2/5
then the second sentance
50<36x-16
add 16 to both sides
66<36x
divide both sides by 36
1 and 5/6<x
so
since it is and, combine
3 and 2/5>x>1 and 5/6 or
17/5>x>11/6

the solution is
S={x|17/5>x>11/6}

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Let's solve for x.

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Step 2: Add 2b^2 to both sides.

−2b2−x−1+2b2=6b3+869+2b2

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Step 3: Add 1 to both sides.

−x−1+1=6b3+2b2+869+1

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Step 4: Divide both sides by -1.

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Answer:

x=−6b3−2b2−870

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