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Fed [463]
2 years ago
8

Can somebody help me with this equation?

Mathematics
2 answers:
Minchanka [31]2 years ago
8 0

Answer:

-12

Step-by-step explanation:

-9-9-(-6)

-9-9+6

-18+6

-12

Therefore, the answer is -12

Please mark as brainliest.

Kaylis [27]2 years ago
3 0

Answer:

-12

Step-by-step explanation:

-9-9-(-6)

-9-9+6

-18+6

-12

Therefore, the answer is -12

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Find the area of the circle and the sector.
Georgia [21]

Area of a circle is PI x r^2:

Area of circle = 3.14 x 13^2 = 530.66 square meters.

To find the area of the sector multiply the area of the circle by the fraction of the sector

Area of sector = 530.66 x 150/360 = 221.108 square meters ( Round the answer as needed).

6 0
3 years ago
how do you write y - 2 = -(x - 3) in slope-intercept form? A) y = x + 3 B) y = x - 1 C) y = -x + 5 D) y = -3x - 1
SashulF [63]
C) y= -x+5
explain:
y-2=-x+3
y= -x+3+2
so y= -x+5
5 0
2 years ago
What is the value of x? sin49°=cosx
olasank [31]
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49+cos=90
cos=41
3 0
3 years ago
Marge cut 16 pieces of tape for mounting pictures on posterboard each piece of tape is 3/8 inches long how much tape did Marge u
daser333 [38]

Answer:

6 inches of tape

Step-by-step explanation:

To find the total amount of tape that Marge used, you can take the measure of each piece (\frac{3}{8}) and multiply by the total number of pieces cut (16):

\frac{3}{8}*\frac{16}{1}=\frac{48}{8}=6inches

So, Marge used 6 inches of tape altogether.

7 0
3 years ago
Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa
Nataly_w [17]

Answer:

The first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

coefficient of x^{2} in the expansion of (2+x - x^{2})^{6} = (240 - 192) = 48

Step-by-step explanation:

(2+x)^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})

= 6_{C_{0}} \times x^{0} \times 2^{6}  + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4} + terms involving higher powers of x

= 64 + 192 \times x^{1} + 240 \times x^{2} + terms involving higher powers of x

so, the first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

Again,

(2+x - x^{2})^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})

Now, by inspection,

the term x^{2} comes from k =5 and k = 6

for k = 5, the coefficient of  x^{2}  is , (-32) \times 6 = -192

for k = 6 , the coefficient of x^{2} is, 6_{C_{2}} \times 2^{4} = 240

so,   coefficient of x^{2} in the final expression = (240 - 192) = 48

3 0
3 years ago
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