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Varvara68 [4.7K]
3 years ago
14

A set of art exam scores are normally distributed with a mean of

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

The percentage of people that scored less than Calvin is 38.21 %

Step-by-step explanation:

In this question, we are concerned with calculating the percentage of exam scores lesser than what Calvin scores.

To calculate this, we first need to calculate the standard score or the z-score of Calvin result.

Mathematically;

z = (x - mean)/SD

from the question, x = 78, mean = 81 and SD = 10

Substituting this, we have

z = (78 -81)/10 = -3/10 = -0.3

So we proceed to calculate the probability.

P(x < 78) or P(z < -0.3)

We make use of the standard table to get this probability

P(z< - 0.3) = 0.38209

In percentage, this is same as 38.209% or more simply 38.21%

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Svetllana [295]

a) 20.9

    The mean is calculated by adding up the scores and dividing the total by the number of scores, it is also called the average.

    First, we can count and see there are 11 players (makes sense for a football team). Adding up the ages gives us 19 + 19 + 20 + 20 + 20 + 21 + 22 + 22 + 22 + 22 + 23 = 230. Divide by 11 and we get a mean of of about 20.9!

b) 30

To figure this out, we will set up an equation that looks like this:

\frac{19 + 19 + 20 + 20 + 20 + 21 + 22 + 22 + 22 + 22 + 23+x}{12} =22

And now we will solve:

[multiply both sides by 12] 230 + x = 264

[subtract 130 from both sides] x = 30

So the age of the new player should be 30!

Have a nice day!

    I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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Read 2 more answers
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