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olchik [2.2K]
3 years ago
11

There are 750 toothpicks in a regular sized box. If a jumbo box is made by doubling all the dimensions of the regular sized box,

how many toothpicks will the jumbo box hold? (With work pls)
Mathematics
2 answers:
Serga [27]3 years ago
7 0

To answer this, let the 3 sides of the regular sized rectangular box be x, y, and z.

When we double all the sides, the new sides have lengths 2x, 2y, and 2z, respectively.

Since the regular box (with dimensions x,y, and z) have 750 toothpicks, we can write

xyz=750

Similarly we can write for the jumbo box as,

(2x)(2y)(2z)

which is equal to 8(xyz)

So this is 8 times the original of xyz. Hence the jumbo box will have 8 times 750 number of toothpicks.

ANSWER: 8*750=6000 toothpicks

stellarik [79]3 years ago
4 0

Answer:

6000

Step-by-step explanation:

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Step-by-step explanation:

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after another year it becomes

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2 Construct a rational function that will help solve the problem. Then, use a calculator to answer the question.
vaieri [72.5K]

Answer:

<u><em>Dimension of box:-</em></u>

Side of square base = 10 in

Height of box = 5 in

Minimum Surface area, S = 300 in²

Step-by-step explanation:

An open box with a square base is to have a volume of 500 cubic inches.

Let side of the base be x and height of the box is y

Volume of box = area of base × height

                 500=x^2y

Therefore, y=\dfrac{500}{x^2}

It is open box. The surface area of box, S .

S=x^2+4xy

Put  y=\dfrac{500}{x^2}

S(x)=x^2+\dfrac{2000}{x}

This would be rational function of surface area.

For maximum/minimum to differentiate S(x)

S'(x)=2x-\dfrac{2000}{x^2}

For critical point, S'(x)=0

2x-\dfrac{2000}{x^2}=0

x^3=1000

x=10

Put x = 10 into y=\dfrac{500}{x^2}

y = 5

Double derivative of S(x)

S''(x)=2+\dfrac{4000}{x^3} at x = 10

S''(10) > 0

Therefore, Surface is minimum at x = 10 inches

Minimum Surface area, S = 300 in²

7 0
3 years ago
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