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Andru [333]
3 years ago
10

What number makes the equation true? 82 − − 33 = 35

Mathematics
1 answer:
-BARSIC- [3]3 years ago
8 0
First you should subtract the first numbers. 82-33=49
Next, you need to subtract 49- the product, which is 49-35=14
Finally, check your work. 82-14-33=35

I think this is what you mean, at least?
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Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°.
inna [77]

Answer:

First part

The answer is (5 square root 2, 45°), (-5 square root 2, 225°) ⇒ answer (d)

Second part

The equation in standard form for the hyperbola is y²/81 - x²/19 = 1 ⇒ answer(b)

Step-by-step explanation:

First part:

* Lets study the Polar form and the Cartesian form

- The important difference between Cartesian coordinates and

  polar coordinates:

# In Cartesian coordinates there is exactly one set of coordinates

  for any given point.

# In polar coordinates there is an infinite number of coordinates

   for a given point. For instance, the following four points are all

   coordinates for the same point.

# In the polar the coordinates the origin is called the pole, and

  the x axis is called the polar axis.

# The angle measurement θ can be expressed in radians

   or degrees.

- To convert from Cartesian Coordinates (x , y) to

  Polar Coordinates (r , θ)

# r = ± √(x² + y²)

# θ = tan^-1 (y / x)

* Lets solve the problem

- The point in the Cartesian coordinates is (5 , 5)

∵ x = 5 and y = 5

∴ r = ± √(5² + 5²) = ± √50 = ± 5√2

∴ tanФ = (5/5) = 1

∵ tanФ is positive

∴ Angle Ф could be in the first or third quadrant

∵ Ф = tan^-1 (1) = 45°

∴ Ф in the first quadrant is 45°

∴ Ф in the third quadrant is 180 + 45 = 225°

* The answer is (5√2 , 45°) , (-5√2 , 225°)

Second part:

* Lets study the standard form of the hyperbola equation

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the y-axis is

  y²/a² - x²/b² = 1, where

• the length of the transverse axis is 2a

• the coordinates of the vertices are (0 , ±a)

• the length of the conjugate axis is 2b

• the coordinates of the co-vertices are (±b , 0)

•      the coordinates of the foci are (0 , ± c),  

• the distance between the foci is 2c, where c² = a² + b²

* Lets solve our problem

∵ The vertices are (0 , 9) and (0 , -9)

∴ a = ± 9 ⇒ a² = 81

∵ The foci at (0 , 10) , (0 , -10)

∴ c = ± 10

∵ c² = a² + b²

∴ (10)² = (9)² + b² ⇒ 100 = 81 + b² ⇒ subtract 81 from both sides

∴ b² = 19

∵ The equation is  y²/a² - x²/b² = 1

∴  y²/81 - x²/19 = 1

* The equation in standard form for the hyperbola is y²/81 - x²/19 = 1

3 0
3 years ago
A Ferris wheel has a diameter of 50 meters and makes one revolution every 15 minutes
Anni [7]

Answer:

18

Step-by-step explanation:

3 0
3 years ago
AABC is a right triangle. AB=____
rjkz [21]

Since ABC is a right triangle, we can use Pythagorean Theorem to solve for side AB.

Pythagorean Theorem: a^2 + b^2 = c^2

4^2 + 7^2 = c^2

16 + 49 = c^2

65 = c^2

c = 8.06

Hope this helps!! :)

6 0
3 years ago
Read 2 more answers
A polynomial equation with rational coefficients has the roots:​
Sedbober [7]

Answer: (5 - √1) and (4 + √7)

Step-by-step explanation:

Here we have 4 roots, then this is a polynomial of 4th degree.

We can write it as

a*x⁴ + b*x³ + c*x² + d*x + e = 0

We could rewrite this as the product of two quadratic equations:

(a₁*x² + b₁*x + c₁)*(a₂*x² + b₂*x + c₂) = 0

This will be equal to zero when (a₁*x² + b₁*x + c₁) is equal to zero, and when

(a₂*x² + b₂*x + c₂) is equal to zero.

Then we need to find the roots of these two quadratic equations.

And we know that the roots of a quadratic equation like:

a₁*x² + b₁*x + c₁ are given by:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a} = \frac{-b}{2a}   +-\frac{\sqrt{b^2 - 4ac}}{2a}

Then the general form of the roots is something like:

A +-\sqrt{B}

This means that if one of the roots is:

5 + √1, we must have another root equal to 5 - √1

And if we have one root equal to 4 - √7, then we must have another root equal to 4 + √7

Then the correct options are:

(5 - √1) and (4 + √7)

5 0
3 years ago
BRAINLIEST ASAP! LENGTH OF AC?
Levart [38]

Answer:

2.33 units

Step-by-step explanation:

\tan 25\degree =\frac{AC}{5}\\\\0.46630 = \frac{AC}{5}\\\\AC = 0.46630 \times 5\\AC =2.3315\\AC = 2.33 \: units

6 0
3 years ago
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