We know that
applying the law of cosines
a² = b²+ c²<span> – 2*b*c*cos(A)
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in this problem
a=?
b=20
c=9
A=90°
so
a² = b²+ c² – 2*b*c*cos(A)
but
cos (A)=0
a² = b²+ c²-----> 20²+9²----> a²=400+81----> a²=481-----> a=√481
a=21.93-----> a=22
the answer is
22
Answer:
Step-by-step explanation:
Okay, first we need to figure out what one would make. We need to figure out the area of the base x height. The diameter is 8 so we will cut that to 4 so we can do piR2! 3.14x16 would be 50.24. Then we mutiply that by 10 to get 502.4cm3! Okay, now we would divide 2000/502.4 to find out how many times we would have to make the containers to get to 2000. The answer is 3.98, which we will have to round up since its asks for the minimum and you cant make a container 3.98 times. So the answer is 4!
Here is my answer. Let just give assumptions. For example,the relationship is linear.Therefore the slope, "m," is the same throughout.
Let us make patrons the independent variable, the two points are: (1314, 11333) and (1544, 13518).
m = (13518-11333)/(1544-1314)
m = 9.5
profit = 9.5 patrons (you pick the variable names)
For 1 more patron substitute 1:
profit = 9.5 (1)
profit = 9.5
Isolate "patrons" and you get the function based on profit:
patrons = profit/9.5
The break even point is for 0 < profit.
0 < profit = 9.5 patrons
0 < 9.5 patrons
0 < patron
Answer:
Answer : A
Step-by-step explanation:
The given data is 25 th percentile is 64, 50th percentile is 74 and 75 th percentile is 80.
percentage : 25 50 75
score : 64 74 80
Median:- The median is obtained by first arranging the data in ascending or descending order and applying the following rule.
If the number of observations is odd, then the median is observation
term
If the number of observations is even, then the median is observation and observations.
given n=3, middle term is '74'
In this given data the median is (M) = 74
Interquartile range IQR = median of upper half-median of lower half
= 80-64
= 16
IQR = 16
