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Ymorist [56]
3 years ago
6

Can someone help please

Mathematics
2 answers:
Airida [17]3 years ago
8 0
Coordinate points on line(-3,-1) and (3,3)

Parallel lines have same slope
so 
m = (3+1)/(3+3) = 4/6 = 2/3

Answer
B. 2/3
rjkz [21]3 years ago
6 0
To compute the slope of a line that passes by two ponits A and B we use the formula : 
m=\dfrac{y_B-y_A}{x_B-x_A}
Use this formula to answer your question.

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You are measuring the height of a statue. You stand 17 feet from the base of the statue. You measure the angle of elevation from
olga_2 [115]

Answer:

height ≈ 31 ft

Step-by-step explanation:

The illustration below will form a right angle triangle. He is standing 17 ft away from the base of the statue.  The angle of elevation from the ground to the top of the statue  is 61°. The height of the statue can be computed below.

adjacent side of the triangle = 17 ft

opposite side = a

Using SOHCAHTOA principle

tan 61° = opposite/adjacent

tan 61° = a/17

cross multiply

a = 17 tan 61°

a = 17 × 1.80404775527

a = 30.6688118396

a ≈ 31 ft

6 0
3 years ago
What is the solution to the quadratic equation?<br> y = x^2-4
Anika [276]

(-2,2)

i just did my homework with the same question

7 0
3 years ago
What is the initial value of the equation shown?
hodyreva [135]
C. −6, is the best option
7 0
3 years ago
Read 2 more answers
17. Evaluate each pair of expressions.<br> a. (-3)-8 and -3-8<br> b. (-3)-9 and -3-9
Semmy [17]
A = -11
B= -12

This is because of how calculations work in negatives. Because they are both negative they work similarly to addition
5 0
3 years ago
Help if u know it please!!!
Ulleksa [173]
Mean: add all the numbers, then dived the sum by hwo many numbers there are.
72.3 + 74.5 + 81.1 + 72.3 + 75.6 + 79 = 754.8
754.8 ÷ 6 = 75.8
Mean = 75.8°

Median: Put all the number in order from lowest to highest. The middle number is the median. If there are two numbers in the middle, add them then divide the sum by 2.
72.3, 72.3, 74.5, 75.6, 79, 81.1
74.5 + 75.6 = 150.1
150.1 ÷ 2 = 75.05 ~ 75
Median = 75°
5 0
3 years ago
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