Answer: 12 students
Step-by-step explanation:
Let X and Y stand for the number of students in each respective class.
We know:
X/Y = 2/5, and
Y = X+24
We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:
(Y-x)/(X+x) = 1
---
We can rearrange X/Y = 2/5 to:
X = 2Y/5
The use this value of X in the second equation:
Y = X+24
Y =2Y/5+24
5Y = 2Y + 120
3Y = 120
Y = 40
Since Y = X+24
40 = X + 24
X = 16
--
Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:
(Y-x)=(X+x)
(40-x)=(16+x)
24 = 2x
x = 12
12 students must transfer to the more difficult, very early morning, class.
Mean: [45+65+30+50+20+30]/6 = 40.2
Median
First order the number {20, 30, 30,45, 50, 50}
The median is the average of the two values in the middle of the list: (30+45)/2 = 37.5
Mode: 30 and 50 (they are repeated the same number of times)
Answer:
the second one but I'm not sure it cuz it was a little bit different in my text I hope it
We are trying to find the number that when added to 19, gives us less than 42. We can set up this simple inequality:
19 + x < 42
Now, subtract 19 from both sides:
x < 23
Our number can be anything less than 23.
Answer:
x = 50
Step-by-step explanation:
101 + (x + 29) = 180
130 + x = 180
x = 180 - 130
x = 50