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3 years ago

find 3 consecutive integers such that 3 times the sum of the first and third is 84 less than 12 times the secind

1 answer:

8 0

Let x = 1st integer
x + 1 = 2nd integer
x + 2 = 3rd integer
3(x + x + 2) = 12(x + 1) - 84
3(2x + 2) = 12x + 12 - 84
6x + 6 = 12x - 72
-6x = -78
x = 13
Answer: 13, 14, 15

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Answer:

C. 76.81

Step-by-step explanation:

We must use one of the trigonometric ratios to find the length, L, of the ramp. If we use 16 as the reference angle, the 22 in would be our opposite side and the ramp length is the adjacent.

Therefore, we must use tan, which is $\frac{opposite}{adjacent}$ :

$tan (16)=\frac{22}{L} \\\\L*(tan(16)=22)\\\\L*tan(16)=22\\$

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

See question above ^^

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3 years ago

The graph shows the savings in Andre’s bank account.

Vadim26 [7]

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Step-by-step explanation:

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3 years ago

. A special safe lets you choose from 9 symbols for a 3-symbol-long pass code. You may enter a symbol any number of times. How m

Lady_Fox [76]

The question is an illustration of combination and there are 729 potential pass codes available

<h3>How to determine the number of potential pass codes?</h3>

The given parameters are

Symbols available = 9

Length of pass code = 3

From the question, we understand that a symbol may be entered any number of times.

This means that each of the 9 available symbols can be used three times

So, the number of potential pass codes is

Passcodes = 9 * 9 * 9

Evaluate the product

Passcodes = 729

Hence, there are 729 potential pass codes available