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chubhunter [2.5K]
3 years ago
8

K² = 76What is the answer?​

Mathematics
2 answers:
Simora [160]3 years ago
6 0

Answer:

± 8.7178 or ± the square root of 19

Step-by-step explanation:

Solve  :    k2-76 = 0

Add  76  to both sides of the equation :

                     k2 = 76

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  

                     k  =  ± √ 76  

Can  √ 76 be simplified ?

Yes!   The prime factorization of  76   is

  2•2•19

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 76   =  √ 2•2•19   =

               ±  2 • √ 19

The equation has two real solutions  

These solutions are  k = 2 • ± √19 = ± 8.7178  

Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

k = 2 √ 19 , − 2 √ 19

Step-by-step explanation:

Take the root of both sides and solve.

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3 years ago
Find the least common denominator for these
baherus [9]

Answer:

The least common denominator of the two rational expressions is (x+2)^{2}\cdot (x+3).

Step-by-step explanation:

Let be the following rational expressions:

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Then, we factor each denominator:

\frac{x^{3}}{(x+2)^{2}}, \frac{-9}{(x+3)\cdot (x+2)}

Now, we compare each denominator to find all missing binomials so that each expression may have a common denominator:

\frac{x^{3}}{(x+2)^{2}} \rightarrow (x+3)

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8 0
3 years ago
Eric has $25 to purchase magazines and to pay for his lunch. Each
faust18 [17]

Answer:

B

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8 0
3 years ago
Given the function:
anyanavicka [17]
You are correct. The answer is choice D

The only way for g(x) to be differentiable at x = 0 is for two things to happen
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(2) g ' (x) is continuous at x = 0

To satisfy property (1) above, the value of b must be 1. This can be found by plugging x = 0 into each piece of the piecewise function and solving for b. 

So the piecewise function becomes
g(x) = \begin{cases}x+1 \ \text{ if } \ x \ < \ 0\\ \cos(x) \text{ if } \ x \ge 0\end{cases}
after plugging in b = 1

--------------------------------

Now differentiate each piece with respect to x to get
g'(x) = \begin{cases}1 \ \text{ if } \ x \ < \ 0\\ -\sin(x) \text{ if } \ x \ge 0\end{cases}
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Because -sin(x) = -sin(0) = 0

So there's this disconnect on g ' (x) meaning its not continuous

Therefore, the value b = 1 will not work. 

So there are no values of b that work to satisfy property (1) and property (2) mentioned at the top. 

5 0
3 years ago
1. Solve for x. Show your work.<br> 2x-1/2=3-x
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5 0
4 years ago
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