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4 years ago

A force can never act by itself?

2 answers:

6 0

An object can never act on itself. Forces related to Newton's third law apply to different bodies, therefore they cannot cancel each other out. For example, the reaction to Earth's gravitational pull on the Moon is the Moon's pull on Earth.
I hope I helped you :)

Diano4ka-milaya [45]4 years ago

5 0

Answer:

true

Step-by-step explanation:

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6. Suppose the population of deer in a state forest is given by the function D(t) = 750 + 150 cos

ki77a [65]

Yes he answer is A B C

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3 years ago

Explain how to use a pattern to find the product of a power of 10 and a decimal? Please help

ArbitrLikvidat [17]

: Explain patterns in the number of zeros of the product when multiplying a number by powers of 10, and explain patterns in the placement of the decimal point when a decimal is multiplied or divided by a power of 10. Use whole-number exponents to denote powers of 1

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4 years ago

A survey of statistics students who had completed BUS 203 revealed that 70% sought additional help at the ICC Learning Lab, whil

Musya8 [376]

Answer:

a) P(NP/L) = 0.1

b) P(P/L) = 0.9

c) P(P) = 0.666

d) P(L/P) = 0.945

e) P(NL U NP) = 0.37

Step-by-step explanation:

given that;

P = passing the course, NP = Not passing the course, L = Using lab, NL = not using Lab

P(L) = 70% = 0.7, P(NL) = 30% = 0.3

P(P/L) = 90% = 0.9

P(P/NL) = 12% = 0.12

the probability of not passing the course given that the student went to the Learning Lab

P(NP/L) = 1 - P(P/L)

P(NP/L) = 1 - 0.9

P(NP/L) = 0.1

the probability of using the Learning Lab and passing the course

P(P/L) = 0.9

the probability of passing the class

P(P) = P(P/L) * P(L) + P(P/NL) * P(NL)

= (0.9 * 0.7) + (0.12 * 0.3)

P(P) = 0.666

the probability that a student utilized the Learning Lab given the condition that the student passed the class

P(L/P) = [P(P/L) * P(L)] / P(P)

P(L/P) = (0.9 * 0.7) / 0.666 = 0.63/0.666

P(L/P) = 0.945

the probability of not using the Learning Lab or not passing the class

P(NL U NP) = P(NL) + P(NP) - P(NP n NL)

= 0.3 + 0.334 - (0.88 * 0.3 )

= 0.634 - 0.264

P(NL U NP) = 0.37

4 0

4 years ago

A school teacher is worried that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the s

kompoz [17]

Answer: At a 5% significance level, the critical value is <u>1.690</u>.

Step-by-step explanation:

Let $\mu$ denotes the average concentration of radon gas.

Given : A school teacher is worried that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the safe level of 4pCi/L.

As per given , the appropriate hypothesis to test :

$\text{Null hypothesis }:H_0:\mu\leq4$