Question

Alejandro ran 15 3 over 10 yards during one play of a football game. During the next play, he ran 2 over 3 of that distance. How many yards did he run during the second play?
A .10 1/5 yd
B .22 19/20 yd
C .5 1/10 yd
D .15 1/5 yd

Answer 1

The answer to you’re question is definitely A. 10 1/5 yd

Answer 2

Answer:

A: 10$\frac{1}{5}$ YD

Here's what to do:

1. Change the mixed number to an improper fraction.

15  $\frac{3}{10}$ = $\frac{150}{10}$ + $\frac{3}{10}$ =  $\frac{153}{10}$

2. Multiply the numerator by the other numerator that needs to be multiplied and do the same for the denominator. Here, let me explain.

$\frac{153}{10}$ x $\frac{2}{3}$. When you muliply this, multiply the numerator by the numerator (153 x 2), and the denominator by the denominator (10 x 3). You should get your answer of $\frac{306}{30}$ (because you put the product of the numerators in the numerator and the same for the denominator).

3. This is the correct answer, but you still need to convert this back to the numerator and simplify.

a. If you can use a calculator, just divide 306 by 30, and when you get 10.2, you know that 10.2 = 10 $\frac{2}{10}$ = 10$\frac{1}{5}$

b. If you can't though, instead of 306, divide 300 by 30, which should give you 10, and add the remaining 6/30 (300/30 + 6/30 = 306/30, or the answer), which equals 2/10 which essentially equals 1/5, and you add the bolded numbers, which gives you 10$\frac{1}{5}$, or A.

Hope this helps :)

-jp524