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3 years ago

Circumference formula for a cylinder to find the volume

Mathematics

1 answer:

muminat3 years ago

3 0

Volume of the cylinder is given by V=πr2h

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In Canada, households spent an average of $80.63 CDN monthly for high-speed broadband access.24 Assume that the standard deviati

ELEN [110]

Answer:

Step-by-step explanation:

Assuming a normal distribution for the amount spent by Canadian households for high-speed broadband access, the formula for normal distribution is expressed as

z = (x - u)/s

Where

x = amount spent by the Canadian households.

u = mean amount spent monthly.

s = standard deviation

From the information given,

u = $80.63 CDN

s = $27.32 CDN

We want to find the probability that the average amount will exceed $85. It is expressed as

P(x greater than 85) = 1 - P(x lesser than or equal to 85)

For x = 85

z = (85 - 80)/27.32 = 0.18

Looking at the normal distribution table, the corresponding z score is 0.57142

P(x greater than 85) = 1 - 0.57142 = 0.43

3 0

3 years ago

Classify ∠1 and ∠2 using all names that apply<br><br> Given: m∠1 = 28° and m∠2 = 62°

Igoryamba

Answer:

complementary angle

hope it helps.

4 0

3 years ago

Plz help i need answers ASAP

Ira Lisetskai [31]

U need to show us the problem not answers help

4 0

3 years ago

Which is the following is the set of real zeros of the function f(x) = (x3 + 1000)(x4 - 160,000)?

marusya05 [52]

Answer:

A. { -20, -10, 20 }

Step-by-step explanation:

Given:

The function is given as:

$f(x)=(x^3+1000)(x^4-160000)$

Let us simplify the function.

First, we use the identity $a^3+b^3=(a+b)(a^2-ab+b^2)$

$x^2+1000= x^3+10^3=(x+10)(x^2-10x+10^2)\\x^3+1000=(x+10)(x^2-10x+100)$

Next, we use the identity $a^4-b^4=(a-b)(a+b)(a^2+b^2)$

$x^4-160000=x^4-20^4=(x-20)(x+20)(x^2+20^2)=(x-20)(x+20)(x^2+400)$

Now, the function can be rewritten as:

$f(x)=(x+10)(x^2-10x+100)(x-20)(x+20)(x^2+400)$

Now, the zeros are those values of $x$ for which $f(x)=0$

Now, for $f(x)=0$ , we must have either of the factors 0.

$x+10=0\\x=-10$

$x-20=0\\x=20\\\\x+20=0\\x=-20$

The factors $x^2-10x+100$ and $x^2+400$ can have no zeros as the first one has imaginary roots and second one is always greater than 0 irrespective of the $x$ values.

So, the possible set of zeros are { -20, 10, 20 }.

6 0

4 years ago

A spinner has four equal sections labeled one through four you spin the spinner once what is the probability the arrow will land

krek1111 [17]

Seventy-five percent

7 0

4 years ago