Sprry, I don't speak spanish, really wish I could've helped. If anyone reading this knows spanish, please comment and tell me what the question is asking.
8/52 because there are 4 3’s in a deck and 4 jacks in a deck
Answer:
(a) yes
(b) no; see below
Step-by-step explanation:
(a) Integer roots of the quartic will be integer divisors of 6. One of the divisors of 6 is 3, so 3 is a possible root.
(b) In order for 3 to be a double root, it would have to be a double factor of 6. The only integer factors of 6 are 1, 2, 3, 6. (3² = 9 is not one.)
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The quartic can be written as ...
k(x -a)(x -b)(x -c)(x -d) . . . . . where a, b, c, d, k are integers
The constant term will be kabcd, of which each of the roots is a factor. If the constant is 6 and one root is d=3, then we must have
kabcd = 3kabc = 6
kabc = 6/3 = 2
Among these four integer factors, there must be an even number of minus signs, and one that has the value ±2. Another root whose value is 3 will not satisfy the requirements.
Answer:
X=16
Step-by-step explanation:
10x-8=9x+8
First you have to simplify.
10x-9x=1x
So now the equation looks like this
x-8=8
Now you have to get x by itself
-8+8=0 and we have to do the same thing on both sides of the equal sign 8+8=16
The equation now looks like this x=16
And that's your answer
Answer:
10+5x
Step-by-step explanation: First 3x becomes a neggative thus saying there is a minus infront of it then combine the like therms with 8x making it 5x. Once you do that take 7 and add it to 3. Therefore the answer is 5x+10.
