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xxMikexx [17]
3 years ago
10

Write the three forms of the line parallel to the line represented by the equation, 8x+3y=11 such that it passes through the poi

nt (9, -5).
Mathematics
1 answer:
Misha Larkins [42]3 years ago
6 0

Answer:

  • 8x + 3y = 57
  • y = -8/3x + 19
  • y + 5 = -8/3(x - 9)

Step-by-step explanation:

<u>Given function</u>

  • 8x+3y=11

<u>Line parallel to the given has the same slope and passes through the point </u>

  • (9, -5)

<u>Determining the equation</u>

  • 8x + 3y = c
  • 8*9 + 3*(-5) = c
  • c=72 - 15
  • c = 57

<u>So the function is in </u><u>standard</u><u> form</u>

  • 8x + 3y = 57

<u>Converting to </u><u>slope-intercept</u><u> form</u>

  • y = mx + b
  • 3y = -8x + 57
  • y = -8/3x + 573
  • y = -8/3x + 19

<u>Point-slope</u><u> form, using the given point</u>

  • y - y1 = m(x - x1)
  • y - (-5) = -8/3(x - 9)
  • y + 5 = -8/3(x - 9)

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x1 and x2 are in the desired interval [-2, 2]

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so we have:

3x^2 - 4x - 4 = 0

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<h3>What is interval notation?</h3>

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We have:

Continuous set of all numbers between 5 and 6, including 5, but not including 6.

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Since both denominators of the fractions are different, you have to find the least common multiple of 7 and 8

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