Answer:
Value of stamp collection = (45b + 43) cents
Step-by-step explanation:
What we have here is as follows;
if there are x 3-cent stamps, then there are 4x 10-cent stamps
So the number of 2-cent stamps is 1 less than 3 cent stamps and that will be x-1 2 cent stamps
Number of 2 cents stamps = b
This means that x-1 = b
Thus, x = b + 1
So the value of the stamp collection is as follows;
x 3 cents stamps = 3(b+ 1) = 3b + 3 cents
4x 10 cents stamps = 10(4(b + 1)) = 10(4b + 4) = 40b + 40
value of the 2 cents stamp = 2b cents
Total value is thus;
2b + 40b + 40 + 3b + 3 = (45b + 43) cents
Answer:
Large boxes are 18.25 kg
Small boxes are 15.25 kg
Step-by-step explanation:
This is a system of equations. You need to set up each equation first.
I am assigning x to be big boxes and y to be small boxes.
5x + 3y = 137
2x + 6y = 128
To solve, you will need to eliminate a variable. That means you will have to multiply one of the equations by a number to make it so a variable will be eliminated. I will be multiplying the top equation by -2.
-2 ( 5x + 3y = 137)
2x + 6y = 128
Distribute the -2 to everything in the parentheses in the first equation.
-10x - 6y = -274
2x + 6y = 128
Notice the 6y will go away because -6y + 6y = 0. Now add the equations together. The remaining equation is:
-8x = -146
Solve for x by dividing by -8.
x = 18.25
Now plug that into one of the original equations.
2(18.25) + 6y = 128.
36.5 + 6y = 128 Subtract 36.5 from each side
-36.5 -36.5
6y = 91.5 Divide by 6 to solve
y = 15.25
21216 i multiplyed 5304 x 4
