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3 years ago

Is it right for people to get credit for an answer if they looked it up?

Mathematics

2 answers:

son4ous [18]3 years ago

8 0

Answer: I mean if you can summarize the answer and put it in your on answer then yeah.

Step-by-step explanation:

Kobotan [32]3 years ago

6 0

Yes.
Why?
They worked hard to get that answer by typing things and typing requires work.
Which means credit should be earned

Thank you for your time

You might be interested in

Find the HCF of 960 and 432

sdas [7]

Answer:

Step-by-step explanation:

Using Uclid's division algorithm, the HCF of 960 and 432 can be obtained as follows:

Here, 960 is greater and 432 is smaller. We divide 960 by 432.

STEP 1:

960 = 432*2 + 96

STEP 2:

Divide divisor (432) by remainder (96)

432 = 96 * 4 + 48

STEP 3:

Divide divisor (96) by remainder (48)

96 = 48 * 2 + 0

Since, remainder at this step is zero (0), so the HCF would be the divisor of this step which is 48.

Thus, HCF of 960 and 432 is 48

4 0

2 years ago

exam p A drawer contains four pairs of socks, with each pair a different color. One sock at a time is randomly drawn from the dr

Marta_Voda [28]

Answer:

The probability that the maximum number of draws is required is 0.2286

Step-by-step explanation:

The probability that the maximum number of draws happens when you pick different colors in the first four pick.

Assume you picked one sock in the first draw. Its probability is 1, since you can draw any sock.

In the second draw, 7 socks left and you can draw all but the one which is the pair of the first draw. Then the probability is $\frac{6}{7}$

In the third draw, 6 socks left and you can draw one of the two pair colors which are not drawn yet. Its probability is $\frac{4}{6}$

In the forth draw, 5 socks left and only one pair color, which is not drawn. The probability of drawing one of this pair is $\frac{2}{5}$

In the fifth draw, whatever you draw, you would have one matching pair.

The probability combined is 1× $\frac{6}{7}$ × $\frac{4}{6}$ × $\frac{2}{5}$ ≈ 0.2286

5 0

3 years ago

A cube of wood measures 9 cm on a side and weighs 28 grams what is the density of the cube of wood

77julia77 [94]

Answer:

25 grams

Step-by-step explanation:

6 0

3 years ago

Determine whether each of the binary relation R defined on the given sets A is reflexive, symmetric, antisymmetric, or transitiv

ki77a [65]

Answer:

In explanation

Please let me know if something doesn't make sense.

Step-by-step explanation:

*This relation is not reflexive.

0 is an integer and (0,0) is not in the relation because 0(0)>0 is not true.

*This relation is symmetric because if a(b)>0 then b(a)>0 since multiplication is commutative.

*This relation is transitive.

Assume a(b)>0 and b(c)>0.

Note: This means not a,b, or c can be zero.

Therefore we have abbc>0.

Since b^2 is positive then ac is positive.

Since a(c)>0, then (a,c) is in R provided (a,b) and (b,c) is in R.

*The relation is not antisymmretric.

(3,2) and (2,3) are in R but 3 doesn't equal 2.

*This relation is reflective.

Since a^2=a^2 for any a, then (a,a) is in R.

*The relation is symmetric.

If a^2=b^2, then b^2=a^2.

*The relation is transitive.

If a^2=b^2 and b^2=c^2, then a^2=c^2.

*The relation is not antisymmretric.

(1,-1) and (-1,1) is in the relation but-1 doesn't equal 1.

*The relation is reflexive.

a/a=1 for any a in the naturals.

*The relation is not symmetric.

Wile 4/2 is an integer, 2/4 is not.

*The relation is transitive.

If a/b=z and b/c=y where z and y are integers, then a=bz and b=cy.

This means a=cyz. This implies a/c=yz.

Since the product of integers is an integer, then (a,c) is in the relation provided (a,b) and (b,c) are in the relation.

*The relation is antisymmretric.

Assume (a,b) is an R. (Note: a,b are natural numbers.) This means a/b is an integer. This also means a is either greater than or equal to b. If b is less than a, then (b,a) is not in R. If a=b, then (b,a) is in R. (Note: b/a=1 since b=a)

6 0

3 years ago

Can someone explain this to me? I'm not entirely sure this question has enough information to be solved. Thanks!

dedylja [7]

Question 1

$DC=AC-AD=20-16=4$

Question 2

By the geometric mean theorem,

$BD^2 = (4)(16)=64 \\ \\ BD=8$

Question 3

By the Pythagorean theorem,

$AB^2 = 8^2 + 16^2 \\ \\ AB^2 = 320 \\ \\ AB=8\sqrt{5}$

Question 4

By the Pythagorean theorem,

$BC^2 = 8^2 +4^2 \\ \\ BC^2 = 80 \\ \\ BC=4\sqrt{5}$

8 0

1 year ago