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AleksAgata [21]
3 years ago
9

Incoming students at a school are assigned six-digit ID numbers. The first digit is chosen at random from the digits 0 through 3

. The remaining five digits are chosen at random from the digits 0 through 9. What is the probability that an incoming student is assigned an ID number that begins with the digits 012? Enter your answer in the box.
Mathematics
2 answers:
Vesna [10]3 years ago
6 0
For the sequence of events, the probability of being assigned 012 is:

P(012)=(1/4)(1/10)(1/10)

P(012)=1/400   (0.25%)
Setler [38]3 years ago
6 0
P(012) = (1/4)(1/10)(1/10)

P(012) = 1/400   .... 0.25%
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\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}\to &
\begin{array}{llll}
8000
\end{array}\\
pymnt=\textit{periodic payments}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
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\end{cases}

\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]
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