Answer: the two numbers are 46 and 37
Step-by-step explanation:
Given that:
Sum of two numbers = 83
Sum of two times the first number and three times the second number = 203
From the question :
Let the numbers = a and b respectively
a + b = 83 - - - (1)
2*a + 3*b = 203
2a + 3b = 203 - - - (2)
From (1) :
a + b = 83
a = 83 - b
Substitute a = 83 - b into (2)
2(83 - b) + 3b = 203
166 - 2b + 3b = 203
166 + b = 203
b = 203 - 166
b = 37
From;
a + b = 83
a = 83 - b
a = 83 - 37
a = 46
Answer:
The photo attached could be of use
Step-by-step explanation:
Well first u have to figure out the stuff in parentheses
The answer
the full the question is as follow:
<span>Which of the following is an extraneous solution of (45 - 3x)^1/2 =x -9
for solving such an equation, this is the method:
finding the squared value of each member of the equation
</span>[(45 - 3x)^1/2 ]² = (x -9)² (E)
<span>
extend each value of the member
</span>[(45 - 3x)^1/2 ]² = 45 - 3x, because (sqrt a )² = a
the condition is 45 - 3x≥0 ( because of the square root)
it means - 3x≥ -45 and x ≤ 15
(x -9)² = x²-18x + 81
<span>
so </span>45 - 3x = x²-18x + 81, this is equivalent to x² - 15x +36 =0
<span>
this equation should solve for x, for finding the help
Delta = 15² - 4*36 = 81, so x = - (-15) - sqrt (81) / 2 *1=15-9 /2= 3
and </span>x = - (-15) +sqrt (81) / 2 *1= 15 +9/2= 24/2=12
<span>
for x= 12, the equation given above ( equation E) has no solution, because
we can find 3=9
so </span><span>an extraneous solution is x = 12</span><span>
</span>
Answer:
12
Step-by-step explanation:
213 multiplied by 0 divided and add parenthese by 283 multiplied by 516, and add a parenthese, and add, and add a parenthese by 120 multiplied by 10 divided by 100.
