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Gennadij [26K]
3 years ago
8

BC = 4x + 2 AB = 8x + 8 and AC = 22 Find BC

Mathematics
1 answer:
Scilla [17]3 years ago
8 0

Answer:

BC = 6.8

Step-by-step explanation:

The distance from A to B, then from B to C, is the same distance as from A to C.

Thus,

AB + BC = AC

AB = 8x + 8

BC = 4x + 2

AC = 22

AB + BC = AC

(8x + 8) + (4x + 2) = 22

Expanding the parenthesis:

8x + 8 + 4x + 2 = 22

8x + 4x + 8 + 2 = 22

12x + 12 = 22

Subtracting 12 from both sides:

12x = 10

Dividing both sides by 12:

x = 10/12 = 1.2

x = 1.2

We're looking for BC. As we know,

BC = 4x + 2

Let's now put in x = 1.2 into this equation:

BC = 4x + 2

BC = 4 * 1.2 + 2

Since 4 * 1.2 is 4.8:

BC = 4.8 + 2

BC = 6.8

Answer: BC = 6.8

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Larissa plans to bake at most 10 loaves of bread. She makes x loaves of banana bread that sell for $1.25 each and y loaves of nu
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Answer:

1) The system of inequalities are;

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Please find attached the required graph of the two inequalities ,created with Microsoft Excel

2) The graph of inequality shows that Larissa cannot to make less than 10 loafs of bread and sell them for over $24 at the given prices of each loaf of bread

Step-by-step explanation:

1) The maximum number of loaves Larissa plans to make = 10

The price at which she sells each of x loaves of banana bread = $1.25

The price at which she sells each of y loaves of nut bread = $1.50

The total amount she hopes to make = $24

The system of inequalities are;

x × 1.25 + y × 1.5 ≥ 24

x + y ≤ 10

Making y the subject of both inequalities gives;

For the first inequality, we have,

y ≥ 24/1.5 - 1.25/1.5·x which gives;

y ≥ 16 - 5/6·x

For the second inequality, we have,

y ≤ 10 - x

Please find attached the required graph of the two inequalities

2) From the attached graph of inequality, created with Microsoft Excel, it shows that it is not possible for Larissa to make less than 10 loafs of bread and at the same time sell them for over $24 if the price of each banana bread is $1.25 and the price of each nut bread is $1.50.

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Answer:

<h3>  (2x - 1) 4</h3>

STEP

1

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Equation at the end of step 1

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STEP  

2

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Equation at the end of step

2

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STEP  

3

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Equation at the end of step

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