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Makovka662 [10]
3 years ago
8

1. Find 1% of a number: a) 400 b) 2,500 c) 657 d) 12

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
5 0

Step-by-step explanation:

a) \: 1\%  \: of \: 400 =  \frac{1}{100}  \times 400 = 4 \\  \\ b) \: 1\%  \: of \: 2500 =  \frac{1}{100}  \times 2500 = 25 \\  \\ c) \: 1\%  \: of \: 657=  \frac{1}{100}  \times 657 = 6.57 \\  \\ d) \: 1\%  \: of \: 12=  \frac{1}{100}  \times 12 = 0.12 \\

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I need help with this someone very smart in math this is algebra 2
PilotLPTM [1.2K]

Answer:

D

Step-by-step explanation:

The interest is compounded annually, which means that interest from the previous year earns you even more money next year.

It should be obvious that after one year Alexis will have

$475 + $475 * 1.25% = $475 * 100% + $475 * 1.25% =

= 101.25% * $475 = 1.0125 * $475

Then, next year she would have

1.0125 * $475 + (1.0125 * $475) * 1.25% =

= (1.0125 * $475) * 1.0125 = 1.0125^2 * $475

See the pattern?

Alexis will have $475 * 1.0125^x after x years.

8 0
3 years ago
The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance betw
shusha [124]
We know that
circumference=2*pi*r-------> r=circumference/(2*pi)
circumference=30 in
r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in
the radius of a <span>standard basketball is 4.77 in
</span>
<span>the distance between the ball and the rim is equal to
</span>radius of a basketball rim minus radius of a a standard basketball  
radius of a basketball rim =18/2------> 9 in
radius of a a standard basketball=4.77 in<span>

</span>
the distance between the ball and the rim=[9-4.77]------> 4.23 in

the answer is
4.23 in
3 0
4 years ago
Read 2 more answers
Suppose you have one pyramid with a base that is 10 meters long and 10 meters wide with a slant that is 15 meters. Now, if the l
marishachu [46]

Answer:

The difference between area of pyramids is 125 sq.m.

Step-by-step explanation:

Length of base = 10m

Breadth of base = 10 m

Slant height = 15 m

Area of pyramid = Area of 5 bases

Area of pyramid = \frac{1}{2} \times 10 \times 15+\frac{1}{2} \times 10 \times 15+\frac{1}{2} \times 10 \times 15+\frac{1}{2} \times 10 \times 15+10 \times 10

Area of pyramid = 400 sq.m.

Now the length of base is increased to 15

Length of base = 15m

Breadth of base = 10 m

Slant height = 15 m

Area of pyramid = Area of 5 bases

Area of pyramid =\frac{1}{2} \times 15 \times 15+\frac{1}{2} \times 15 \times 15+\frac{1}{2} \times 10 \times 15+\frac{1}{2} \times 10 \times 15+10 \times 10

Area of new pyramid = 525 sq.m.

Difference between area of pyramids=525 sq.m. - 400 sq.,. = 125 sq.m.

Hence The difference between area of pyramids is 125 sq.m.

4 0
4 years ago
Javier is saving for a new pair of shoes that costs $59.99. So far, he has saved $22.50. How much more does he need to save? Sho
Neko [114]

Answer:

hi there user!

The answer is he needs to save $37.49 more

Step-by-step explanation:

59.99 - 22.50 = 37.49

8 0
3 years ago
Find the length of the second leg of the triangle round to the nearest hundredth
horsena [70]

Answer:

\displaystyle \frac{3\sqrt{230}}{5}

Step-by-step explanation:

Use the Pythagorean Theorem:

\displaystyle a^2 + b^2 = c^2 \\ \\ 9,7^2 + b^2 = 13,3^2; \sqrt{82,8} = \sqrt{b^2} \\ \\ \frac{3\sqrt{230}}{5}\:[or\:9,0994505329...] = b

So, you have this:

\displaystyle 9,1 ≈ b

I am joyous to assist you at any time.

7 0
3 years ago
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