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Ber [7]
3 years ago
15

Please help me, I'm stuck on this question.

Mathematics
2 answers:
ASHA 777 [7]3 years ago
8 0

Since the triangle is isosceles, then (x + 4) must be equal (3x - 8)

Solving the (x + 4) = (3x - 8), we'll get:

(x + 4) = (3x - 8)

3x - x = 8 + 4

2x = 12

x = 6

So, the length of AC is 6 units

never [62]3 years ago
6 0

Step-by-step explanation:

AC=AB+BC

AC=x+4+3x‐8

COMBINE LIKE TERMS

AC=x+3x

AC =4x+4‐8

=4x+‐4

=0

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sam and jose mowed 2/3 of the yard. jose mowed 3/4of that amount. whta part of the yard did jose mow?
guapka [62]

Answer:

09

Step-by-step explanation:

34

3 0
2 years ago
A researcher conducted a hypothesis test to see if students on average spend more than 1 hour per homework assignment. The level
grandymaker [24]

Answer:

a. True

Step-by-step explanation:

By ∝= 5% we mean that there are about 5 chances in 100 of incorrectly rejecting a true null hypothesis. To put it in another way , we say that we are 95% confident in making the correct decision.

In the given question the null hypothesis is

H0: u ≤ 1 hour and Ha:  u > 1 hour

So there is a 5% chance that the erroneous conclusion will be made that students spend on average more than 1 hour per assignment.

The given statement is true.

5 0
3 years ago
A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes
marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

V = s^2h = 5324

h = 5324 / s^2

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top s^2

Side area 4sh

Total surface area A = s^2 + 4sh

We can substitute h = 5324 / s^2

A = s^2 + 4s\frac{5324}{s^2}

A = s^2 + 21296/s

To find the minimum of this function, we can take the first derivative, and set it to 0

A' = 2s - 21296/s^2 = 0

2s = 21296/s^2

s^3 = 10648

s = \sqrt[3]{10648} = 22

h = 5324 / s^2 = 5324 / 22^2 = 11

4 0
3 years ago
What is the length of the cylinder's height? Please help​
raketka [301]

Answer:

  • Height = <u>9</u><u> </u>cm which means <u>Option </u><u>C </u>is the answer

Step-by-step explanation:

In the question we are given ,

  • Volume of cylinder = <u>2</u><u>2</u><u>5</u><u>π</u><u> </u><u>cm³</u>

  • Radius of cylinder = <u>5 cm</u>

And , we have to find the <u>height</u><u> of</u><u> </u><u>cylinder</u><u> </u>.

We know that ,

\longrightarrow \pink{ \boxed{Volume \:  of \:  Cylinder = \pi r {}^{2}h  }} \longleftarrow

Our solution starts from here :

\longmapsto \: \pi \: r {}^{2} h = 225\pi

<u>Step </u><u>1</u><u> </u><u>:</u> Cancelling π with π :

\longmapsto \:  \cancel{\pi} \: r {}^{2} h = 225 \cancel{\pi}

<u>Step </u><u>2</u><u> </u><u>:</u> Substituting value of radius which is 5 cm in the formula :

\longmapsto \: (5) {}^{2}  \times h = 225

\longmapsto \: 25h = 225

<u>Step </u><u>3 </u><u>:</u> Transposing 25 to right hand side :

\longmapsto \: h =  \frac{225}{25}

<u>Step </u><u>4</u><u> </u><u>:</u> Cancelling 225 by 25 :

\longmapsto \:   \red{\boxed{h = 9 \: cm}}

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>height</u><u> </u><u>of </u><u>cylinder</u><u> is</u><u> </u><u>9</u><u> </u><u>cm</u>

<h2 /><h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
8 0
1 year ago
Answer this equation: 4 3/5 - -3 2/5 + 3
horrorfan [7]

Answer:

24

Step-by-step explanation:

4\frac{3}{5} -(-3\frac{2}{5})+3

Negative and another negative makes a positive.

4\frac{3}{5}+3\frac{2}{5}+3

Add the fractions first.

7\frac{5}{5}+3

5/5 is equivalent to 1. 7 5/5 becomes 8.

8+3

Add the numbers.

24

I hope this helps!

6 0
3 years ago
Read 2 more answers
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