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bija089 [108]
3 years ago
11

What is the domain of the function y=3 in x graphed below?

Mathematics
2 answers:
Semenov [28]3 years ago
4 0

Answer:

domain is x>0

Step-by-step explanation:

y=3ln(x)

domain is the set of x values for which the function is defined

ln(negative value ) is undefined

So we take positive values for x because we have ln(x)

From the graph we can see that the given equation has a graph for x values greater than 0

the graph goes close to 0 but does not crosses y axis

So domain is x>0

Jet001 [13]3 years ago
3 0
What is the domain of the function y=3 in x graphed below?

Domain is x>0, ln (0) is undefined and there is no negative ln.
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Answer:

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Step-by-step explanation:

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You offer senior citizens a 20% discount on their tune-ups at your gas station. Assuming that an average of 50 senior citizens g
GREYUIT [131]
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I JUST WANNA PASS MY SOPHOMORE YEAR BUT I SUCK AT MATH!!!!! PLEASE HELP!!!!!!
Natasha2012 [34]

Mr. Sanchez's class: 1.65p

Mr. Kelly's class: 1.36j

where p = fruit pies and j = fruit juice

____________________________________________________________

(a) Creating a system of equations

p + j = 79

1.65p + 1.36j = 118.17

are your system of equations

____________________________________________________________

(a) Solving the system of equations for p and j

Solve for p in the first equation. Subtract j from both sides.

p = 79 - j

____________________________________________________________

Plug p into the second equation.

1.65(79 - j) + 1.36j = 118.17

Distribute 1.65 inside the parentheses.

130.35 - 1.65j + 1.36j = 118.17

Combine like terms.

130.35 - 0.29j = 118.17

Subtract 130.35 from both sides.

-0.29j = -12.18

Divide both sides by -0.29.

j = 42

____________________________________________________________

Plug j into the first equation.

p + (42) = 79

Subtract 42 from both sides.

p = 37

____________________________________________________________

(b) To find out how much each class earned

Now plug in p and j into Mr. Sanchez's class and Mr. Kelly's class equations (at the top).

Mr. Sanchez's class: 1.65(37) = 61.05

Mr. Kelly's class: 1.36(42) = 57.12

____________________________________________________________

(c) To see how much more Mr. S's class earned

Subtract 57.12 from 61.05.

61.05 - 57.12 = 3.93

____________________________________________________________

(a)

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(b)

Mr. Sanchez's class earned more money (61.05 > 57.12).

(c)

Mr. Sanchez's class earned $3.93 more than Mr. Kelly's class.

3 0
3 years ago
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