1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shtirlitz [24]
3 years ago
7

What is the total perimeter of the pitch and seating area?

Mathematics
2 answers:
Vlad [161]3 years ago
5 0

Answer:

The total Perimeter of the pitch and seating area is 179.83 m an the Total Area is 1394 m²

Step-by-step explanation:

Figure is attached with required naming.

Length of the Rectangle 1 = 40 m

width of the Rectangle 2 = 2000 cm = 20 m

radius of semi circle 2 = \frac{2000}{2}=1000=10\,m

radius of semi circle 3 = \frac{2000}{2}=1000=10\,m

length of the rectangle 4 = 25 m

width of the rectangle 4 = 800 cm = 8 m

length of the rectangle 5 = 10 m

width of the rectangle 5 = 800 cm = 8 m

Total Perimeter of the pitch and seating area

= length of rectangle 1 + circumference of semi circle 2 + circumference of semi circle 3 + length of rectangle 4 + 2 × width of rectangle 4 + length of rectangle 5 + 2 × width of the rectangle 5 + (length of rectangle 1 - length of rectangle 4 - length of he rectangle 5)

= 40 + π(10) + π(10) + 25 + 2 × 8 + 10 + 2 × 8 + ( 45 - 25 -10 )

= 40 + π(10) + π(10) + 25 + 16 + 10 + 16 + 10

= 117 + 20π

= 179.83 m (approx.)

Total area of the pitch and seating area

= Area of the Rectangle 1 + Area of semi circle 2 + area of semi circle 3 + area of rectangle 4 + area of rectangle 5

= 40 × 20 + π(10)² + 25 × 8 + 10 × 8

= 800 + 100π + 200 + 80

= 1080 + 314

= 1394 m²

Therefore, The total Perimeter of the pitch and seating area is 179.83 m an the Total Area is 1394 m²

natima [27]3 years ago
4 0
1m = 100 cm

so
40 m = 4,000 cm
25 m = 2,500 cm
10 m = 1,000 cm

perimeter of big rectangle = 2(4,000 + 2000) = 12,000 cm
perimeter of small rectangle on the left: 2(2,500 + 800) = 6,600 cm
perimeter of small rectangle on the right: 2(1,000 + 800) = 3,600 cm
perimeter of circle = πd = 3.141593 x 200 = 628.32 cm

total area of the pitch and seating area :
=  12,000 + 6,600 + 3,600 + 628.32 = 22,828.32<span> cm

answer
</span>22,828.32 cm<span>

</span>
You might be interested in
The emergency brake cable in a truck parked on a steep hill breaks and the truck starts rolling down the hill. The distance in f
topjm [15]

Answer:40.5

Step-by-step explanation:

5 0
2 years ago
Which of the following could be a solution to a system of linear equations including the line graphed below?
Anna [14]

Answer:

B

Step-by-step explanation:

using quadratic equation

3 0
3 years ago
On January 24, Bora Co. purchased a delivery van for $22,000. Bora expects to drive the van for approximately 5 years or 100,000
Assoli18 [71]

Answer:

$24,000

Hope this helps

3 0
3 years ago
Read 2 more answers
How do I solve 8×-2=-9+7×
muminat

The answer is 9/23 you simply both sides of the equation, subtract 7x from both sides, divide both sides by -23

8 0
3 years ago
Read 2 more answers
What is the area of a shape with points a 5 -8 b 11, -8 c 11,0 d 6,-3 e 4,-3
Dmitriy789 [7]

Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

                                         = 11 × 8

                                         = 88 square units

Area of trapezoid OGEF = \frac{1}{2}(b_1+b_2)\times h

                                         = \frac{1}{2}(\text{GE+OF)}\times (\text{OG})

                                         = \frac{1}{2}(3+6)\times 4

                                         = 18 units²

Area of trapezoid GCDE = \frac{1}{2}(\text{GC+DE)}\times (\text{GE})

                                         = \frac{1}{2}(7+2)\times 3

                                         = 13.5 units²

Area of triangle AFH = \frac{1}{2}(\text{Base})\times (\text{Height})

                                  = \frac{1}{2}(5)(2)

                                  = 5 units²

Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

                                           = 88 - (18 + 13.5 + 5)

                                           = 88 - 36.5

                                           = 51.5 units²

Therefore, area of the given polygon is 51.5 units²

3 0
3 years ago
Other questions:
  • 5 times 60 equals 5 times how many tens
    5·1 answer
  • Find the circumference and Area of a circle with radius 7 yd<br> Use the value 3.14 to help
    12·1 answer
  • Given the perimeter of a​ square, find the length of one side using the appropriate formula.
    12·1 answer
  • A trig function given below. Describe the transformations from
    5·1 answer
  • Find the sum 3a/bc + 2b/ac
    15·1 answer
  • How do you write 2.77 × 102 in standard form?
    14·1 answer
  • Rewrite the linear expression by factoring out the coefficient of the variable. -1/2x +6
    10·2 answers
  • Lavonne estimated 38% of 63 by rounding 38% up to 40% rounding 63 up to 70 and then multiplying 70 by 0.4 to get 28 . Is her est
    8·2 answers
  • Compare Loan Terms
    12·2 answers
  • Hi what is the circumstances 3rd to be ​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!