Let
x-------> the number of dinner
y-------> the number of lunch
we know that
-------> equation A
------> equation B
Substitute equation B in equation A
![8[y]+5y \leq 42](https://tex.z-dn.net/?f=8%5By%5D%2B5y%20%5Cleq%2042)
so
the greatest number of lunch is 
Hence
the greatest number of dinner is 
therefore
the greatest number of meals is
<u>the answer is</u>
C because scientific notation has to be number between 1-10
Answer:
-4432.5 m . . . or . . . -4.4325 km
Step-by-step explanation:
You can use the formula for average velocity, fill in the given values, and solve for displacement.
average velocity = displacement/time
-98.5 m/s = displacement/(45 s)
Multiply by time:
(-98.5 m/s)(45 s) = displacement = -4432.5 m
_____
Keeping units with the numbers serves as a check on the math. (m/s)·s = m. The units work the same way variables do: they can be multiplied and divided, raised to a power, canceled. If the units of the problem don't work out right, you're probably doing it wrong. (Note, you can only add and subtract numbers that have the same (identical) units--the same rule as for combining like terms.)
Answer:
Option D is correct.
Step-by-step explanation:
f(x)= 9x^2 -12
Let y = 9x^2 - 12
Switch places of x and y and solve for y
x = 9y^2 - 12
Adding 12 on both sides
x + 12 = 9y^2
Dividing both sides by 9
x+12/9 = y^2
=> Taking square root on both sides
=> 
Replace y with g(x)
Option D is correct.
