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7nadin3 [17]
3 years ago
8

What would be a situation in which you could use an excel chart to present your data

Computers and Technology
2 answers:
quester [9]3 years ago
7 0

Answer

Excel charts can be used where;

• Comparing information, you can use column charts

• Showing trends, you can use line charts to show whether values are increasing or decreasing with time

Explanation

Charts are used in excel because they show more than the sheet and numbers contained. Vertical bars are applied in column charts in excel to represent data for comparing information. Different charts can accept a variety of data to be presented for interpretation. Trends are ideally shown by line charts, where a connection of the lines could mean an increase or decrease of a certain trend.



Pavlova-9 [17]3 years ago
5 0
Having to compare results on experiments or lab tests to each other.
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Write an application that instantiates five Recording objects and prompts the user for values for the data fields. Then prompt t
tangare [24]

Answer:

Here is the JAVA application

Recording.java:

class Recording {  //class name

String title;  //String type variable to store the title of the song

String artist;  //String type variable to store the artist name of the song

int playingTime;  //int type variable to store the playing time of the song in seconds  

public String getTitle() {  //accessor method to get the title of the song

   return title; }   //returns the current title of song

public void setTitle(String title) {  //mutator method to set the title of song

   this.title = title;  }   // sets the title of song

public String getArtist() {  //accessor method to get the artist name of the song

  return artist; }   //returns the current artist name of song

public void setArtist(String artist) {  //mutator method to set the artist name of song

  this.artist = artist; }   //sets the artist name

public int getPlayingTime() {  //accessor method to get the playing time of the song

   return playingTime; } /  /returns the playing time of song

public void setPlayingTime(int pt) {  //mutator method to set the playing time of song

   this.playingTime = pt; }   //sets the playing time of song

public Recording(String title, String artist, int playingTime) {  //parmeterized constructor of Recording class that takes title, artist and playingTime as parameters

this.title = title;  

this.artist = artist;

this.playingTime = playingTime;  }  }

Explanation:

Here is the Main class:  

import java.util.Scanner;   //to accept input from user

public class Main {  

public static void main(String[] args) {  // start of main function

 Recording[] song = new Recording[5];  //creates object of Recording class named song to instantiate five Recording objects

 Scanner input = new Scanner(System.in);  //creates Scanner class object named input

 int i = 0;  // declare i and initialize it to -

 for (i = 0; i < song.length; i++) {  //iterates through the list of song

  int j = i + 1;  

  System.out.print("Enter the title of song " + j + ": ");  //prompts user to enter the title of song

 String title = input.nextLine();   //reads the title string from user

 System.out.print("Enter the artist of song " + j + ": ");  //prompts user to enter the artist of song

 String artist = input.nextLine();   //reads the artist string from user

System.out.print("Enter the playing time of song " + j + " in seconds: ");   //prompts user to enter the playing time of song

 String playtime = input.nextLine();  //reads the playing time string value from user

 int playingTime = Integer.parseInt(playtime);   // converts String value of playtime to integer

 song[i] = new Recording(title, artist, playingTime); }   //calls constructor of Recording class by passing title, artist and playingTime to it  

 int sort;  // for choosing which field to sort

do {  //continues to ask user to enter which field the Recordings should be sorted by

System.out.println("How should these songs be sorted? 1 for title 2 for artist 3 for playing time");  

sort = input.nextInt();  //reads user choice to sort

       if (sort > 0 && sort < 4) {  //to check if user enters a valid choice

 int a, b;  

 int max = song.length - 1;  

for (a = 0; a < max; a++) {  //iterates through the length of the song list setting an index variable a

      for (b = 0; b < max; b++) {    //iterates through the length of the song list setting an index variable b

  int c = b + 1;

     if (sort == 1) {  //if the user selects title field

       if (song[b].getTitle().compareTo(song[c].getTitle()) > 0) {  // compares title of one song with the song that comes after it

   Recording temp = song[b];  //sorts the titles using bubble sort by ordering each title to the immediate next and swapping them if they are not sorted already

   song[b] = song[c];

   song[c] = temp; } }  

   else if (sort == 2) {    //if the user selects artist field

  if (song[b].getArtist().compareTo(song[c].getArtist()) > 0) {  // compares artist of one song with the song artist  that comes after it

//sorts the artists using bubble sort by ordering each title to the immediate next and swapping them if they are not sorted already

     Recording temp = song[b];

     song[b] = song[c];

     song[c] = temp;  }  }  

   else if (sort == 3) {   //if the user selects playing time field

  if (song[b].getPlayingTime() > song[c].getPlayingTime()) {

/* compares artist of one song with the song artist  that comes after it sorts the artists using bubble sort by ordering each title to the immediate next and swapping them if they are not sorted already */

       Recording temp = song[b];

        song[b] = song[c];

         song[c] = temp;  } } } }  }  

             else {  //if user enters any invalid choice

 System.out.println("Invalid choice! Enter right choice"); }        

       } while (sort < 1 || sort > 3);  //keeps asking user to enter which field the recording to sort by until the value of sort in range of 1 to 3

for (i = 0; i < song.length; i++) {  //displays the sorted song list according to selected field

System.out.println("Song: Title: " + song[i].getTitle() + ". Artist: " + song[i].getArtist() + ". Playing time: " + song[i].getPlayingTime() + " seconds.");  }

input.close();  }  }

The output of the program is attached.

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3 years ago
The shortest compressed format of the ipv6 address 2001:0db8:0000:1470:0000:0000:0000:0200 is
devlian [24]

The answer is : 2001:DB80:1470::200

A double colon ( :: ) can replace any single, contiguous string of one or more 16-bit segments (hextets) which is  consist of all 0s, and it can only be used once per IPv6 address. Therefore,any leading 0s (zeros) in any 16-bit section or hextet can be omitted.

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3 years ago
Very Short Answer Type Question (any 9)
Lubov Fominskaja [6]

Answer:

home page (also written as homepage) is the main web page of a website.

Ans 2

6 0
2 years ago
Which of the following statements holds true for the term "html"? It refers to a system that connects end users to the Internet.
Oksana_A [137]

Answer:

Your answer is B. It refers to the language used to create and format Web pages.

Explanation:

HTML stands for "Hyper Text Markup Language", which is a specification used on any webpage, ever. It was created by Sir Tim Berners-Lee in late 1991 and was officially released in 1995. This language is actually what is sent to your browser, which then interprets it and allows you to see the pretty pictures of Brainly.com! As of right now, HTML is at it's 5th revision, also known as HTML5, which is another term you'll see around.

Thanks, let me know if this helped!

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Given the following schedule, show the locks that will occur and the subsequent schedule. Assume that strict 2PL is in effect, w
Alexxandr [17]

Answer:

see explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem

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