Assuming the first 5 terms are:
n = 0
n = 1
n = 2
n = 3
n = 4
a) 4n + 4
4(0) + 4 = 4
4(1) + 4 = 8
4(2) + 4 = 12
4(3) + 4 = 16
4(4) + 4 = 20
b) 8n + 3
8(0) + 3 = 3
8(1) + 3 = 11
8(2) + 3 = 19
8(3) + 3 = 27
8(4) + 3 = 35
c) 18 - 3n
18 - 3(0) = 18
18 - 3(1) = 15
18 - 3(2) = 12
18 - 3(3) = 9
18 - 3(4) = 6
Answer:
B [2,∞)
Step-by-step explanation:
There are no numbers without decimals which multiply to 78 and add up to 17.
Answer:
P = 0.0438 ; We reject the Null and conclude that there is significant evidence that the discharge limit per gallon of waste has been exceeded.
Due to the small sample size.
Step-by-step explanation:
H0: μ = 500
H1 : μ > 500
Test statistic :
(xbar - μ) / S.E
Tstatistic = (1000 - 500) / 200
= 500 / 200
= 2.5
Pvalue from Test score ; df = 4 - 1 = 3 ; using calculator :
Pvalue = 0.0438
At α = 0.05
Pvalue < α ; We reject the Null and conclude that there is significant evidence that the discharge limit per gallon of waste has been exceeded.
The test above has a very small sample size, and for a distribution to be approximately Normal, the sample size must be sufficiently large enough according to the Central limit theorem.
For a two sided analysis ; the Pvalue is twice that for the one sided, hence, Pvalue = (0.0438 * 2) = 0.0876 yielding a less strong evidence against the Null.
Answer: (2x+4y=150) this is right
i
swear
on
my
mama
this
is
correct
my
g
