Well, the quotient must be bigger/smaller
lets say the numbers are x and y
x>y
so
x-y=30 and x/y=6
multiply both sides by y in 2nd equation
x=6y
subsitute 6y for x in other equation
6y-y=30
5y=30
divide by 5
y=6
sub back
x=6y
x=6(6)
x=36
the numbers are 36 and 6
but they could also be -36 and -6 because -36/-6=6 and -6-(-36)=30
the 2 numbers are 36 and 6 or -36 and -6
Answer:
(3x^2+ 2x+ 1) - (x^2- 3x+ 4)
Correct Simplification:
3x^2+ 2x +1 - x^2 + 3x - 4
2x^2 + 5x - 3
Ans C
He did not multiply the - for -3x
Hope it helps you.
Answer:
= sqrt(53)
Step-by-step explanation:
|7-2i| means find the distance
d = sqrt(real part^2 + imaginary part^2)
= sqrt(7^2 + (-2)^2)
= sqrt(49+4)
= sqrt(53)
To find X, set up a ratio with the given dimensions:
10/15 = X/42
Cross multiply:
420 = 15x
Divide both sides by 15:
x = 420 / 15
x = 28
Answer:
The coordinates of the point are (-3,-5)
Step-by-step explanation:
Here, we want to find the coordinates of the point that divides the segment in the ratio 3:2
We shall use the internal division formula;
(x,y) = (mx2 + nx1)/(m + n) , (my2 + ny1)/(m+ n)
Where in this case;
(x1,y1) = (6,-2)
(x2,y2) = (-9,-7)
(m, n) = 3,2
Substituting these values;
(x,y) = (3(-9) + 2(6))/(3+2) , (3(-7) + 2(-2))/(3+2)
(x,y) = (-27 + 12)/5 , (-21 -4)/5
(x ,y) = (-15/5, -25/5)
(x , y) = (-3,-5)
