2 years ago

Determine the value of x if the mode is 18

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

8 0

Nobody can solve this without any further information?

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Pls help me answer this question from least you greatest

Tanzania [10]

Answer: the answer is D

7 0

2 years ago

Read 2 more answers

Rita earns $16.00 per hour. If she gets a 6% raise, what will be her new hourly wage?

miskamm [114]

16.00 * 6% would be 00.96
her new wage would be $16.96

5 0

3 years ago

15.7 is what percent of 785

ehidna [41]

Answer:

Step-by-step explanation:

15.7 is 2% of 785

Hope this helps :)

6 0

2 years ago

-7=2+ w<br><br> Help please

ziro4ka [17]

Answer:

w= -9 :)

Step-by-step explanation:

5 0

2 years ago

Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo

nlexa [21]

Given:

Equation of line $7x-4y=-12$ .

To find:

The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

Solution:

The given equation of line can be written as

$7x-4y+12=0$

Slope of line is

$\text{Slope}=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}$

$m_1=-\dfrac{7}{(-4)}$

$m_1=\dfrac{7}{4}$

Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is

$m_1m_2=-1$

$m_2=-\dfrac{1}{m_1}$

$m_2=-\dfrac{4}{7}$ $[\because m_1=\dfrac{7}{4}]$

Now, the slope of perpendicular line is $m_2=\dfrac{4}{7}$ and it goes through (-21,2). So, the equation of line is

$y-y_1=m_2(x-x_1)$

$y-2=-\dfrac{4}{7}(x-(-21))$

$y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)$

$y-2=-\dfrac{4}{7}x-12$

$y=-\dfrac{4}{7}x-12+2$

$y=-\dfrac{4}{7}x-10$

Therefore, the required equation in slope intercept form is $y=-\dfrac{4}{7}x-10$ .

7 0

2 years ago