The answer is that y is equal to -3 and x is equal to 7
2x-y=17
-2(x-y)=10 )
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2x-y=17
-2x+2y=-20
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y=-3

x-y=10
x-(-3)=10
x+3=10
-3 -3
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x=7

8 0

2 years ago

What is the solution of the equation 3^5 sqrt (x+2)^3+3=27?

BlackZzzverrR [31]

3^5) (x + 2)^(3/2) + 3 = 27
(x + 2)^(3/2) = 24 / 243 
x + 2 = [ 24 / 243 ]^(2/3) 
x + 2 = [ 8 / 81 ]^(2/3) 
x = [ 4 / 81^(2/3) ] - 2 =-1.786

the answer is x=-1.786

4 0

2 years ago

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Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se

kolbaska11 [484]

Answer:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

Step-by-step explanation:

Given:

The expression to expand is given as:

$(x-3)(x-9)(x-4)$

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

$(a + b)(c + d) = ac + ad + bc + bd$

$(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27$

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

$(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)$

Therefore, the equivalent expression after expanding is given as:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

3 0

2 years ago

Simplify the following expression [ (3x6) ] + (5x2) ] ÷ 7

KonstantinChe [14]

[ (3x6) ] + (5x2) ] ÷ 7
= (18 + 10)/7
= 28/7
= 4

6 0

3 years ago

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