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Annette [7]
3 years ago
5

What is the value of the expression when a=5, b=4 and c=6? 4a/2b-c A.9 B.2 C.10 D.5

Mathematics
2 answers:
Montano1993 [528]3 years ago
4 0
Hey, Ill help you <span><span><span>‌<span><span>4a</span><span>2b</span></span></span>‌</span>−c</span><span>
a=5
b=4
c=6
 Evaluate!</span> Evaluate for <span><span><span>a=5</span>,<span>b=4</span></span>,<span>c=6</span></span><span><span><span>‌</span></span></span><span><span><span><span><span><span>(4)</span><span>(5)</span></span><span><span>(2)</span><span>(4)</span></span></span></span>‌</span>−6</span><span><span><span>‌</span></span></span><span><span><span><span><span><span>(4)</span><span>(5)</span></span><span><span>(2)</span><span>(4)</span></span></span></span>‌</span>−6</span><span>
</span><span>=<span><span>‌<span><span>−7/</span>2</span></span>‌</span></span><span>(Decimal: -3.5)</span><span />

<span>
</span>

<span>The answer is not there</span>

<span>
</span>


nirvana33 [79]3 years ago
3 0

Answer:

The answer is 10

Step-by-step explanation:

4(5)/2(4)-6

20/2(4)-6

2*4-6=2

20/2=10


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Simplify 12(6)-7(2)+(6-3)
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Andrew is selling tickets for the school play, and charges t dollars for adult tickets and 2 dollars for child tickets. On Monda
Andru [333]

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T=4 plz make brainlest answer

Step-by-step explanation:

Monday overall cost 36+5t

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3 0
3 years ago
The general form of a circle is given as x^2+y^2+4x - 12y + 4 = 0. A) What are the coordinates of the center of the circle? B) W
Alex_Xolod [135]

Answer:

center = (-2, 6)

radius = 6

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

(where (a, b) is the center and r is the radius)

Therefore, we need to rewrite the given equation into the standard form of an equation of a circle.

Given equation:

x^2+y^2+4x-12y+4=0

Collect like terms and subtract 4 from both sides:

\implies x^2+4x+y^2-12y=-4

Complete the square for both variables by adding the square of half of the coefficient of x and y to both sides:

\implies x^2+4x+\left(\dfrac{4}{2}\right)^2+y^2-12y+\left(\dfrac{-12}{2}\right)^2=-4+\left(\dfrac{4}{2}\right)^2+\left(\dfrac{-12}{2}\right)^2

\implies x^2+4x+4+y^2-12y+36=-4+4+36

Factor both variables:

\implies (x+2)^2+(y-6)^2=36

Therefore:

  • center = (-2, 6)
  • radius = √36 = 6
7 0
2 years ago
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