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ziro4ka [17]
3 years ago
8

Simplify (4x + 2) x 3

Mathematics
1 answer:
Elza [17]3 years ago
7 0
The answer should be 12x squared + 6x if not 12x+6
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grandma gigi gave leyla a rare purple stone for her sweet 16 birthday. at that time,the stone was worth$245. it has been increas
sergij07 [2.7K]
This is a compound interest problem, therefore s(t) should be in the form:
s(t) = a(r)^{t}

where: 
t = time in years
s(t) = the value of your item after t years
a = the initial value of your item
r = rate

Therefore, we already know that a = 245$.

Now, we can calculate r:
r^{t}=\frac{s}{a}
r =  \sqrt[t]{ \frac{s}{a} }
r = \sqrt[5]{ \frac{560.50}{245} }
     = 1.18

Therefore, the correct answers are a = 245 and r = 1.18

4 0
3 years ago
Please solve for me. please be right
saveliy_v [14]

Answer:

It would be 60

Step-by-step explanation:

So 3(3*5 + 5) so 3*5 would be 15, 15+5=20, and 20*3=60

This is really simple if you can't figure this out, you might as well go back to 1st grade and below

pls try before asking

4 0
2 years ago
Read 2 more answers
Agustin has 1/4 as many cards as mateo.mateo has 1/2 as amaro.who has the most cards?
Ket [755]

Answer:

amaro

Step-by-step explanation:

amaro has double the amount of cards as mateo and mateo has more than agustin, therefore amaro has the most cards.

5 0
3 years ago
I need big help with this (look at photo) *15 points* please help
irina1246 [14]
|-4| would be 4 because it is the distance from zero or absolute value
7 0
3 years ago
The cost to produce a certain product depends on 3 main variables, denoted p, q, and r. If C(p, q, r) = C0e−2p + 7q − 9r represe
ad-work [718]

Answer:

\sqrt{134}C_0e^{95}

Step-by-step explanation:

We are given that the cost function is  given by

C(p,q,r)=C_0e^{-2p+7q-9r}

\nabla C(p,q,r)=< -2C_0e^{-2p+7q-9r},7C_0e^{-2p+7q-9r},-9C_0e^{-2p+7q-9r}>

We have to find the rate of decrease of this function at the point P_0(100,55,10)

\nabla C(100,55,10)=

\nabla C(100, 55,10)=

\mid \nabla C(100, 55, 10)\mid=\sqrt{(-2C_0e^{95})^2+(7C_0e^{95})^2+(-9C_0e^{95})^2}

Greatest rate of decrease of this point at the point P_0(100,55,10) is given by

\mid \nabla C(100, 55, 10)\mid=\sqrt{134}C_0e^{95}

7 0
3 years ago
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