<span>80 ft^2
Looking at the figure, you can easily determine that it's made of two separate figures, a rectangle that's 2 feet by 16 feet, and a triangle that has sides of 16 feet, 10 feet, and 10 feet. The triangle can then be divided into two right triangles with a hypotenuse of 10 feet and one leg of 8 feet, so you can use the Pythagorean theorem to calculate the other leg (which is also the height of the large triangle mentioned above). That value is sqrt(10^2 - 8^2) = sqrt(100 - 64) = sqrt(36) = 6.
So we now know that the large 16,10,10 triangle has a base of 16 and a height of 6. So let's calculate the area of the entire figure.
A = 2*16 + 16*6/2
A = 32 + 16*3
A = 32 + 48
A = 80
So the area of the entire figure is 80 square feet.</span>
First you express it as a fraction so that would be 2475/1000 which can be simplified to 99/40
I’m not really sure but I would have to guess 4.5 because all of the other numbers don’t have decimals
Steps to solve:
2(n + 3) = 2n + 3
~Distribute left side
2n + 6 = 2n + 3
~Subtract 6 to both sides
2n = 2n - 3
~Subtract 2n to both sides
n = -3
Best of Luck!
The y-coordinate is between -1 and -2. It is close to halfway between -1 and -2, but it is a little less than halfway.
Answer: Choice B. 
