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svetlana [45]
3 years ago
14

Find the mean and median 0,5,5,9,11,15

Mathematics
1 answer:
il63 [147K]3 years ago
8 0
The mean is 7.5 you add up all the numbers and then divide by the amount of numbers there is
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7 added to the quotient of 6 and 2
coldgirl [10]
6/2=3+7=10
so
(6/2)+7=10
5 0
3 years ago
Y=6(x-7)^2……. any one know this ?
alex41 [277]

Answer: 6x^2-84x+294

Step-by-step explanation:

Use the foil method to solve (x-7)^2 and then multiply your result by 6.

4 0
3 years ago
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What would be A' after I dilation using a scale factor of 1/2
noname [10]

Answer:

A) (-5,0)  

Step-by-step explanation:

B)  (-2, 4)

C)  (-2, -3)

Hope this helped!

8 0
3 years ago
Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A
alekssr [168]

Answer:

\theta_{CAB}=128.316

\theta_{ABC}=25.842

\theta_{BCA}=25.842

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}

AB= \sqrt{(-3-1)^2+(0-3)^2}=5

BC= \sqrt{(1-1)^2+(3-(-3))^2}=9

CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}

\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}

\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}

\theta_{CAB}=\arccos{-\dfrac{0.62}}

\theta_{CAB}=128.316

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}

\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)

\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)

\theta_{ABC}=\arcsin{0.4359}\right)

\theta_{ABC}=25.842

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

\theta_{BCA}=25.842

this can also be checked using the fact the sum of all angles inside a triangle is 180

\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180

25.842+128.316+25.842

180

6 0
3 years ago
Read 2 more answers
PLEASE ANSWER<br><br> Answer Choices:<br> 1# 28.26<br> 2# 15.7<br> 3# 12.56<br> 4# 14.13
Setler [38]

Answer: 2

Step-by-step explanation: because it timed the seconde one so that is why its 2

hope the answer helped :)

7 0
3 years ago
Read 2 more answers
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