Let X be the number of lightning strikes in a year at the top of particular mountain.
X follows Poisson distribution with mean μ = 3.8
We have to find here the probability that in randomly selected year the number of lightning strikes is 0
The Poisson probability is given by,
P(X=k) = 
Here we have X=0, mean =3.8
Hence probability that X=0 is given by
P(X=0) = 
P(X=0) = 
P(X=0) = 0.0224
The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224
Answer: 3j-6k+4
Step-by-step explanation:
First you have to distribute the 3 to the j and the -2k since they are both in the parentheses. So it would look like (3*j) +(-2k*3)+4 and if you simplify that it is 3j-2k+4. After that there are no like terms so that is your answer.
Answer:
I think its B but I have very little evidence. Don't even put B but I was just saying I think it is.
Step-by-step explanation: