The three consecutive integers are: x, (x+1) and (x+2).
We can suggest this equation:
x+(x+1)+(x+2)=126
3x+3=126
3x=126-3
3x=123
x=123/3
x=41
x=41
(x+1)=41+1=42
(x+2)=41+2=43
Answer: the three consecutive integers would be: 41,42 and 43.
Answer:
1 is C and 2 is B
Step-by-step explanation:
Answer:
the answer should be 158 but I'm not a hundred percent sure
... there is no math problem here
try your best i dont understand it propely
