

Multiply eq(1) by 2 and eq(2) by 1




Now
Put in eq(1)






Answer:
Check the attached graph for correct match.
Step-by-step explanation:
Graph of the given choices are not given but we can still solve this problem.
Given equation is 15x-12y=60.
Which is linear equation so we need at least two points to get the graph.
We are free to select any random number of x then plug that into given equation to find other variable.
Let's use x=0
15x-12y=60
15*0-12y=60
0-12y=60
-12y=60
divide both sides by -12
y=-5
Hence point is (0,-5)
Similarly plug y=0
15x-12y=60
15x-12*0=60
15x-0=60
15x=60
divide both sides by 15
x=4
Hence point is (4,0)
Now graph both points then join them by a straight line.
Any graph given in the choices which match with attached graph will be the answer.
Check the attached graph for correct match.
Well, we need to know how much was money the individual started with.
Answer:
v=4
Step-by-step explanation:
-23=3v+9-11v
-23=9-8v
-32=-8v
v=4
It would be a rotation I believe