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AlexFokin [52]
4 years ago
6

Write 5 as a ratio of two integers

Mathematics
2 answers:
k0ka [10]4 years ago
7 0

Answer: 5 as a ratio of two integers is, 5/1 = 5 if it's negative it would show as: -5/1 = -5

tatyana61 [14]4 years ago
5 0

-5 = -5/1

Step-by-step explanation: I believe it’s this I had it right on my question.

Step-by-step explanation:

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What is the surface area of the square pyramid represented by the net?
jeyben [28]
The surface area is 252 m
8 0
3 years ago
The owner of a video game store creates the expression −2x2 + 24x + 174 to represent the store's weekly profit in dollars, where
Semmy [17]

Answer:

-2(x-6)^2+246, x = $6

Step-by-step explanation:

The expression -2x^2+24x+174 to represent the store's weekly profit in dollars, where x represents the price of a new video game.

Let f(x)=-2x^2+24x+174

We need to rewrite this quadratic function in the vertex form.

f(x)=-2(x^2-12x)+174

f(x)=-2(x^2-12x+36)--2(36)+174

f(x)=-2(x^2-12x+36)+72+174

f(x)=-2(x-6)^2+246

The equivalent expression that reveals the video game price that produces the highest weekly profit  is  -2(x-6)^2+246

and the price is $6

6 0
3 years ago
Read 2 more answers
Someone help me please :)
dexar [7]

Answer:

A={5,1,-7}

Step-by-step explanation:

domain = x

choose domain {-2,0,4} to 2x+y=1

range = y

range is

2(-2)+y =1 ,y =5

2(0)+y=1, y= 1

2(4)+ y=1, y=-7

range = {5,1,-7}

3 0
3 years ago
Read 2 more answers
Which of the following is the rational exponent expression of third root of 4 n? A) (4n)3
zhuklara [117]

You have to check which of the following expressions is the rational exponent expression of third root of 4n, or mathematically, \sqrt[3]{4n} . Consider all cases:

A. (4n)^3=4^3\cdot n^3=64n^3\neq\sqrt[3]{4n} .

B. 3n^4\neq \sqrt[3]{4n} .

C. quantity of 4n to the one third power is (4n)^{\frac{1}{3} }=\sqrt[3]{4n} (by the definition of rational power).

D. 4 times n to the one third power is 4\cdot n^{\frac{1}{3} }=4\sqrt[3]{n}\neq \sqrt[3]{4n} .

Answer: correct choice is C.

3 0
4 years ago
Read 2 more answers
The concentration of hexane (a common solvent) was measured in units of micrograms per liter for a simple random sample of sixte
goldenfox [79]

Answer:

Yes, it can be concluded that the mean hexane concentration is less in treated water than in unsaturated water

Step-by-step explanation:

The number of of specimen in the samples of untreated water, n₁ = 16

The sample mean, \overline x_1 = 228.0

The sample standard deviation, s₁ = 4.3

The number of of specimen in the samples of treated water, n₂ = 20

The sample mean, \overline x_2 = 224.6

The sample standard deviation, s₂ = 5.0

The level of significance = 0.10

The null hypothesis, H₀; \overline x_1 ≥ \overline x_2

The alternative hypothesis, Hₐ;  \overline x_1 < \overline x_2

The degrees of freedom = 16 - 1 = 15

The test statistic, t_{\alpha} = 1.341

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}

Plugging in the values, we get;

t=\dfrac{(224.6- 228.0)}{\sqrt{\dfrac{5.0^{2}}{20} -\dfrac{4.3^{2} }{16}}} \approx -11.0675

Given that the t-value is large, the corresponding p-value is low, therefore, we fail to reject the null hypothesis and there is considerable statistical evidence to suggest that the mean hexane concentration is less in treated than in untreated water, therefore, we have; \overline x_1 ≥ \overline x_2

6 0
3 years ago
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