Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
Answer:
I cant really see the questions
Step-by-step explanation:
1) x < 8/3
2) x > -9
3) Infinite Solutions
4) No Solution
Please correct me if I’m wrong. Hope this helps!
Answer:
(10x−7)^2
Step-by-step explanation:
(10x+7)(10x-7)
i stead of making it a "100" since they are both the same but positive and negative () and bring it to the power of 2
Company A pays $5500 more than B in year 10
