Answer:
see explanation
Step-by-step explanation:
Under a clockwise rotation about the origin of 90°
a point (x, y ) → (- y, x ) , then
(3, 3 ) → (- 3, 3 )
(3, 4 ) → (- 4, 3 )
(5, 3 ) → (- 3, 5 )
The vertex of f(x) = 3x^2 + 12x − 8 is (2,28) absolute minimum
<h3>How to determine the vertex?</h3>
The equation is given as:
f(x) = 3x^2 + 12x − 8
Differentiate the function
f'(x) = 6x + 12
Set to 0
6x + 12 = 0
Divide through by 6
x + 2 = 0
Solve for x
x = -2
Substitute x = -2 in f(x) = 3x^2 + 12x − 8
f(2) = 3 *2^2 + 12 *2 − 8
Evaluate
f(2) = 28
This means that the vertex is (2,28)
A quadratic function is represented as:
f(x) =ax^2 + bx + c
When a is positive, then the vertex of the function is an absolute minimum.
This means that f(x) = 3x^2 + 12x − 8 has an absolute minimum vertex because 3 is positive
Read more about quadratic functions at:
brainly.com/question/18797214
#SPJ1
Base = 3.14 x 10 x 10 = 314
height = volume/base
=6908/314
=22 feet
The answer would be =<span>11/<span>20--Welcome , hopes this helps :P</span></span>
Answer and Step-by-step explanation:
a. The strings {a, b, c} with at least one a and at least one b.
Solution: ∑ = {a, b, c}
where
(a +b +c)(a (a +b +c)*b + b (a +b +c) a (a +b +c)*
b. The set of 0’s and 1’s string whose tenth symbol from the right end is 1.
Sol: (0+1)*1(0+1)9
c. The set of 0’s and 1’s string with at most one pair of consecutive 1’s.
sol: (0+10)(11+∑)(0+10)
