2 years ago

What is an equivalent fraction to 9 divided by -12

Mathematics

1 answer:

Xelga [282]2 years ago

4 0

Answer:

3/-4

Step-by-step explanation:

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Given h(t)=-2(t+5)^2+4, find h(-8)

alexandr402 [8]

Substitute -8 for t in h(t)=-2(t+5)^2+4:

h(-8) = -2(-8+5)^2 + 4 = -2(-3)^2 + 4 = -2(9) + 4 = -18 + 4

h(-8) = -18 + 4 = -14 (answer)

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Vlada [557]

80km/h because km is more than miles

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Solve for t: t + 7 = 21 A: t= 28 B: t= 14 C: t= -28 D: t= -14

tatiyna

t + 7 = 21

---Subtract 7 from both sides

t + 7 - 7 = 21 - 7

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2 years ago

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45,645 Rounded to the nearest tens place=45,640

saveliy_v [14]

Answer:The answer is 45,650 is rounded to the nearest tens.

Step-by-step explanation:

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2 years ago

What is the area of △FGH to the nearest tenth of a square meter? The image is of a triangle GHF with base GH length 2m, FG is 2.

Gnesinka [82]

First, we are going to use the law of cosines to find the length of the line segment FH:
$FH= \sqrt{2.5^{2}+2^{2}-(2)(2.5)Cos(121)}$
$FH= \sqrt{2.5^{2}+2^{2}-5Cos(121)}$
$FH=3.2$

Next, we are going to use the semi-perimeter formula: $s= \frac{GH+FG+FH}{2}$
$s= \frac{2+2.5+3.2}{2}$
$s= \frac{7.7}{2}$
$s=3.9$

Now that we have the semi-perimeter of our triangle, we can find its area using Heron's formula:
$A= \sqrt{s(s-GH)(s-FG)(s-FH)}$
$A= \sqrt{3.9(3.9-2)(3.9-2.5)(3.9-3.2)}$
$A= \sqrt{3.9(1.9)(1.4)(0.7)}$
$A=2.7m^{2}$

We can conclude that the area of the triangle GHF is 2.7 $m^{2}$ .

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3 years ago