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3 years ago

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If a number is divided by 3 or 5, the remainder is 1. If it is divided by 7, there is no remainder. What number between 1 and 10

0 satisfies the above conditions?

1 answer:

arlik [135]3 years ago

5 0

Answer:

91

Step-by-step explanation:

Look at multiples of 7 and you’ll find 91.

91 dived by 3 is 30 with a remainder of 1.

91 divided by 5 is 18 with a remainder of 1.

91 divid by 7 is 13 with no remainder.

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But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

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And for the sample variance we have:

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And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

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Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

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