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pav-90 [236]
3 years ago
12

Solve the system of equations

Mathematics
2 answers:
Brums [2.3K]3 years ago
8 0
5x+4y = 73
-4x + 4y = -8

5x + 4y -(-4x+4y) = 73 -(-8)
5x + 4y + 4x - 4y = 81
5x + 4x + 4y - 4y = 81
9x = 81
x = 81÷9
x = 9

Substitute x = 9 into any of the equations to find y.

5(9) + 4y = 73
45 + 4y = 73
4y = 73 - 45
4y = 28
y = 28÷4
y=7

Answers :
x = 9
y = 7
Nadya [2.5K]3 years ago
3 0

Answer:

(9,7)

Step-by-step explanation:

(9,7)

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Answer please to the best of your ability
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Answer:

1.8 m

Step-by-step explanation:

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just replace the T with 2

h=-9.8(2^2)+20(2)+1

-9.8×4+40+1=1.8m

1.8m

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Graph the line with slope -2/5 and y-intercept -3
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
Please help : Find the slope
bija089 [108]

Answer:

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3 0
2 years ago
Read 2 more answers
A 250<br> B 1000<br> C 1750<br> D 5000
PSYCHO15rus [73]

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6 0
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If you replace x2 − y2 with a, 2xy with b, and x2 + y2 with c, what is the identity equation?
ivolga24 [154]
X^2 - y^2 = a

2xy = b

x^2 + y^2 = c

A polynomial identity is an equation that is always true.`1

You can relate x^2 + y^2 with x^2 - y^2 and 2xy in this ways.

1) Step 1:

[x^2 + y^2]^2 = x^4 + 2(xy)^2 + y^4 = c^2

2) Step 2:

[x^2 - y^2] = x^4 - 2(xy)^2 + y^2 = a^2

 (2xy)^2 = 4(xy)^2 = b^2

x^4 - 2(xy)^2 + y^2 + (2xy)^2 = x^4 + 2(xy)^2 + y^2
------------------------    ----------     --------------------------
            ↓                       ↓                        ↓
           a^2                    b^2    =              c^2

Answer: the identity is

c^2 = a^2 + b^2 equivalent to

(x^2 + y^2)^2 = (x^2 - y^2)^2 + (2xy)^2
5 0
4 years ago
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