Question

A survey of

Answer 1

Answer:

0.0208<p<0.0592

Step-by-step explanation:

-Given the sample size is 400 and the desired proportion is 16.

-The confidence interval can be determined as follows:

$CI=\hat p\pm z\sqrt{\frac{\hat p(1-\hat p}{n}}\\\\\hat p=x/n=16/400=0.04$

#We the use this proportion to find the CI at 95%:

$CI=0.04\pm 1.96\times \sqrt{\frac{0.04(1-0.04)}{400}}\\\\=0.04\pm 0.0192\\\\=[0.0208,0.0592]$

Hence, the 95% confidence interval is 0.0208<p<0.0592