Question

X^2+6x-16/3x+15 ×x^2-25/x^2-4x+4

Answer 1

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Answer 2

$\frac{x^{2} + 6x - 16}{3x + 15}(\frac{x^{2} - 25}{x^{2} - 4x + 4})$

Simplify each polynomial by factoring:

$\frac{(x + 8)(x - 2)}{3(x+5)} (\frac{(x - 5)(x + 5)}{(x - 2)(x - 2)})$

Now we cancel out binomials. Notice there is a (x - 2) on both the top and bottom. These cancel each other out. There is also a (x + 5) on both top and bottom so those cancel out as well. 

This leaves you with:

$\frac{(x + 8)(x - 5)}{3(x - 2)}$

This could be your answer OR you could expand it into $\frac{x^{2} + 3x - 40}{3x - 6}$ though I would suggest staying with the former as your final answer.