Answer:
here is only one line of symmetry
Assuming 2032 is itself a number in base 4, you have
![2032_4=2\times4^3+3\times4^1+2\times4^0](https://tex.z-dn.net/?f=2032_4%3D2%5Ctimes4%5E3%2B3%5Ctimes4%5E1%2B2%5Ctimes4%5E0)
Or, if you mean to ask about converting 2032 into base 4, you have
![\dfrac{2032}4=508](https://tex.z-dn.net/?f=%5Cdfrac%7B2032%7D4%3D508)
with remainder 0, which means the "ones" digit is 0.
![\dfrac{508}4=127](https://tex.z-dn.net/?f=%5Cdfrac%7B508%7D4%3D127)
with remainder 0, which means the "tens" digit is also 0.
![\dfrac{127}4=31](https://tex.z-dn.net/?f=%5Cdfrac%7B127%7D4%3D31)
with remainder 3, so the "hundreds" digit is 3.
![\dfrac{31}4=7](https://tex.z-dn.net/?f=%5Cdfrac%7B31%7D4%3D7)
with remainder 3, so the "thousands" digit is also 3.
![\dfrac74=1](https://tex.z-dn.net/?f=%5Cdfrac74%3D1)
with remainder 3, so the next digit is also 3.
![\dfrac14=0](https://tex.z-dn.net/?f=%5Cdfrac14%3D0)
with remainder 1, so the next (and final) digit is 1.
So,
![2032_{10}=133300_4](https://tex.z-dn.net/?f=2032_%7B10%7D%3D133300_4)
.
Answer:
it would take 4 weeks to buy his computer
Step-by-step explanation:
2 weeks=324
the 50 cents in 2 weeks =100
210+324=523
523$ in 2 weeks
523+324=858
856$ in 4 weeks
add the 4 weeks of 50 cents.
50x4=200=2.00$
2.00+858=860$
tadaaaaaa
Step-by-step explanation:
Wesley is approximately
25 miles away from the place he started.
Say, Wesley started from point A, he rowed his boat in north direction, covered 18 miles and stopped at B. From B, he again rowed 18 miles towards east. Finally, he stopped at position C.
From Pythagoras theorem, we can find, AC.
AC² = AB² + BC²
⇒ AC² = 18² + 18²
⇒ AC² = 2×18²
⇒ AC = √2×18 ≈ 25 miles.
I'm not sure what that last string of equalities is, but I think it is Mandy's work. Notice the ratio pattern that she begins with for the first three numbers, it's the output (y) value divided by the input (x) value. Then on the last ratio, she switches the two and divides the input (x) value by the output (y) value. Because of this, she thinks that the last term has a ratio of 1/5, while the others have a ratio of 5. She is incorrect because her common ratio is output divided by input, which is actually 5 for the last term (50/10).