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Llana [10]
3 years ago
15

Let's just talk! just take out the space in the link

Mathematics
2 answers:
Stels [109]3 years ago
8 0

Answer:

I dont have pa d let

Step-by-step explanation:

I have yt doe

Helga [31]3 years ago
4 0

Answer:

No.

Step-by-step explanation:

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What is the answer of 17 and 16 ​
Vera_Pavlovna [14]

Answer:

c)

Step-by-step explanation:

16) Cost price = Selling price  * 100 / (100- loss%)

= 800 * 100 / 80 = 10*100 = 1000

Loss = Cost Price - Selling price = 1000 -800 = 200

6 0
3 years ago
The table below shows the relationship between the buses in the school parking lot and and the number of students on them. What
lawyer [7]

Answer:

Please add the diagram

Step-by-step explanation:

7 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
Suppose that six individuals are interested in taking part in a study relating BMI to a number of health outcomes. The following
posledela

Answer:

a) Mean = 27.65

Median = 27.645

b) Relative Frequency = 33.33%

Step-by-step explanation:

We are given the following data set:

25.78, 21.06, 36.54, 29.51, 18.96, 34.05

a) Mean and Median

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{165.9}{6} = 27.65

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: 18.96, 21.06, 25.78, 29.51, 34.05, 36.54

\text{Median} = \displaystyle\frac{25.78 +29.51}{2} = 27.645

b) BMI above 30 is considered obese

Frequency of obese in the given sample = 2

Relative Frequency =

\displaystyle\frac{\text{Frequency of obese}}{\text{Total number}} = \frac{2}{6} = 0.3333 = 33.33\%

5 0
3 years ago
Graph y=5/3x -9 ......
alisha [4.7K]
Put a point at -9 because that is the y-intercept.then from the point -9 count up 5 and count over 3.
4 0
3 years ago
Read 2 more answers
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