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tekilochka [14]
3 years ago
8

Let's assume you purchase 100 shares of XYZ Company for $1 per share. After three months, the share price increases to $5. This

means the value of the investment has increased from $100 to $500, for a capital gain of $____
Mathematics
1 answer:
denpristay [2]3 years ago
8 0

$400 is the capital gain

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Plz help me!! I need explanation to help me understand a bit.
lozanna [386]
So the figure is called a ray. Which is when there’s a point and than an arrow extends off that point forever. But the way to write a ray is by putting an arrow above it.
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patriot [66]
17.5

5 is the og length. Scale factor is 3.5. So

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3 years ago
Which system of equations would have no solution? pls helpp
Leya [2.2K]

Answer:

3x+y=8 and 3x+y=9

Step-by-step explanation:

Assume these two equations:

a1x+b1y+c1=0

a2x+b2y+c2=0

If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.

In these case, take a look at the last option:

3x  + y = 8 \\ 3x + y = 9

Re-write 'em as a standard form:

3x  + y - 8 = 0 \\ 3x + y - 9 = 0

So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:

\frac{3}{3}  =  \frac{1}{1}  ≠ \frac{ - 8}{ - 9}

And they do not have any collision point

6 0
2 years ago
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Write the number and the nature of the roots of the quadratic equation whose discriminant is -12
Orlov [11]
Hello
<span>D. 2 imaginary roots (complex conjugates)</span>
7 0
3 years ago
You roll a 4-sided die repeatedly. On your odd-numbered rolls (1st,3rd,5th, etc.) you are victorious if you get a 4. On your eve
Sunny_sXe [5.5K]

Answer:

E (Y) = 3

Step-by-step explanation:

If a 4-sided die is being rolled repeatedly; and the odd-numbered rolls (1st 3rd,5th, etc.)

The probability of odd number roll will be, p(T) = \frac{1}{2}

However, on your even-numbered rolls, you are victorious if you get a 3 or 4. Also, the  probability of even number roll, p(U) = \frac{1}{2}

In order to  calculate: E (Y); We can say Y to be the number of times you roll.

We know that;

E (Y) = E ( Y|T ) p(T) + E ( Y|U ) p(U)

Let us calculate E ( Y|T ) and E ( Y|U )

Y|T ≅ geometric = \frac{1}{4}

Y|U ≅ geometric = \frac{1}{2}

also; x ≅ geometric (p)

∴ E (x) = \frac{1}{p}

⇒ \frac{Y}{T} = 4 ; also \frac{Y}{U} = 2

E (Y) = 4 × \frac{1}{2} + 2 ×

        = 2+1

E (Y) = 3

7 0
3 years ago
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