The area of the given square pyramid is:
total area = 1,100 inches squared.
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How to get the area of the pyramid?</h3>
On the second image, we can see that the pyramid is conformed of a square base and 3 triangles.
To get the surface area of the pyramid, we can just get the area of each of these simpler parts.
The base is a square of 22 in by 22 in, then the area of the base is:
B = (22in)*(22 in) = 484 in^2
For each triangle, the area will be:
A = (base side)*(height)/2
A = (22in)*(14in)/2 = 154 in^2
And we have 4 of these triangles, then the total area of the pyramid will be:
total area = B + 4*A = 484in^2 + 4*(154 in^2) = 1,100 in^2
If you want to learn more about square pyramids:
brainly.com/question/22744289
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Since we don't have a figure we'll assume one of them is right and we're just being asked to check if they're the same number. I like writing polar coordinates with a P in front to remind me.
It's surely false if that's really a 3π/7; I'll guess that's a typo that's really 3π/4.
P(6√2, 7π/4) = ( 6√2 cos 7π/4, 6√2 sin 7π/4 )
P(-6√2, 3π/4) = ( -6√2 cos 3π/4, -6√2 sin 3π/4 )
That's true since when we add pi to an angle it negates both the sine and the cosine,
cos(7π/4) = cos(π + 3π/4) = -cos(3π/4)
sin(7π/4) = sin(π + 3π/4) = -sin(3π/4)
Answer: TRUE
Answer:
answer below
Step-by-step explanation:
ABCDE go through dilation over center (6 , -2) with factor of 1/2 to FGHIJ
AB // FG slope: -2 , √20:√5 = 2: 1
BC // GH // X axis 8:4 = 2:1
CD // HI, slope= 1 , √8:√2 = 2:1
DE // IJ // x axis, 4:2 = 2:1
EA // JF // y axis, 2:1
Answer:
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<u>Use quadratic formula:-</u>
᠃ ⚘᠂ ⚘ ˚ ⚘ ᠂ ⚘ ᠃
˱ ┈ ┈ ┈ ┈ ˲
hope it helps...
have a great day!!
Answer:
x = 1
Step-by-step explanation:
x + 8 = 9
=> x = 9 - 8
=> x = 1
