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Sladkaya [172]
3 years ago
9

How you do fractions

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0

Answer:

Step 1: Make sure the bottom numbers (the denominators) are the same

Step 2: Add the top numbers (the numerators), put that answer over the denominator

Step 3: Simplify the fraction (if needed)

Step-by-step explanation:

You might be interested in
(x^3+10x^2+2)/(x+10)
SCORPION-xisa [38]

The quotient is x^2

The remainder is 2

Step-by-step explanation:

We need to divide: \frac{\left(x^3+10x^2+2\right)}{x+10}

The division is shown in figure attached.

The quotient is x^2

The remainder is 2

Keywords: Division of polynomials

Learn more about Division of polynomials at:

  • brainly.com/question/4390083
  • brainly.com/question/4786449

#learnwithBrainly

8 0
3 years ago
Help me please please
Tresset [83]

Answer:

hope its help u

Step-by-step explanation:

let \: the \: angle \: be \:  \alpha  \\  \tan( \alpha )  =  \frac{p}{b}  \\  \tan(32)  =  \frac{25}{x}  \\ 0.62486=  \frac{25}{x }  \\ x =  \frac{25}{0.62486}  \\ x = 40

4 0
1 year ago
adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
2 years ago
Cassie spends 2/3 of her money on supplies. Cassie spends her remaining money on 3 sandwiches. Each sandwich costs $5.25. How mu
Irina18 [472]
In words:
Three sandwiches, each costing $5.25, equals 1/3 of Cassie's total money

We can write the formula:

(5.25*3)=1/3x

Now solve:

15.75=1/3x
3(15.75)=x
x=$47.25
Hope this helps!!
3 0
3 years ago
Read 2 more answers
Please somebody else help me to do . I will mark the correct answer as a brainiest​
vodomira [7]

there is your answer follow and mark me as <em><u>brainliest </u></em>

4 0
2 years ago
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