Answer:
10.32 moles of ammonia NH₃
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 6.21×10²⁴ molecules
Number of mole of NH₃ =?
The number of mole of NH₃ can be obtained as follow:
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole
Therefore,
6.21×10²⁴ molecules = 6.21×10²⁴ / 6.02×10²³
6.21×10²⁴ molecules = 10.32 moles
Thus, 6.21×10²⁴ molecules contains 10.32 moles of ammonia NH₃
Answer:
Explanation:
In order to a molecule or ion have <em>resonance </em>structures (named resonance contributors) it must have a π bond.
π bonds are in double or triple bonds. Single bonds are formed by sigma bonds.
Resonance structures are alternate representations for the same molecule or ion with different structures. Every structure will have the same number of electrons, but the electrons can move from one atom to another, which can only be done between π bonds; never between sigma bonds.
In the ion [NH₄]⁺ there are only sigma bonds: the N atom is at the centre of the iona, bonded to four H atoms; each N - H bond is a sigma bond. So, this structure does not exhibit any resonance.
On the other hand, [NO₃] ⁻ has a double bond between one of the oxygen atoms and the N atom at the centre. So, ion has a π bond, which indicates that there are resonance structures.
Answer:
yep.
Explanation:
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Answer:
Explanation:
Hello,
In this case, considering the ideal gas equation as:
We can first compute the moles of air at the given conditions of 195 kPa (1.92 atm), 10 °C (283K) and 350 L:
Next, since the molar mass of air is 28.97 g/mol, the mass is computed to be:
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